时间:2021-07-01 10:21:17 帮助过:22人阅读
from datasource.db.engine import Base, md from sqlalchemy import Table #表模型 class Bargain(Base): __table__ = Table("tb_bargain", md, autoload=True) 建立 表模型
dbsession.query(Bargain).order_by(desc(Bargain.follow_date)).limit(1).all()
查询时间最大的那一条
follow_obj = follow_dbsession.query(Follow, Employee).join(Employee, Follow.EmpID == Employee.FYEmpID).filter( Follow.FlagTrashed == False, Follow.FlagDeleted == False, Follow.FollowID != "", Follow.DeleteAt.is_(None), Follow.FollowType.in_( [‘业主‘, ‘其他‘, ‘去电‘, ‘售后拜访‘, ‘议价‘, ‘扫雷‘, ‘收意向‘, ‘收意向金‘, ‘来电‘, ‘空看‘, ‘签单‘, ‘签合同‘]), Follow.FollowDate > where2_obj.operation_date) 连表查询
for i in follow_obj: owner_pay_obj = OwnerPay(follow_id=i[0].FollowID, property_id=i[0].PropertyID, employee_id=i[1].EmployeeID, structure_id=i[0].DeptID, operation_date=i[0].FollowDate, data_source="follow_" + str(datetime.datetime.now().year), update_at=time.strftime("%Y-%m-%d %H:%M:%S")) owner_pay_list.append(owner_pay_obj) # 获取;连表查询 数据 连表时返回数据 第一个是数据是第一张表的,索引取1 是第二章表的数据
sqlalchemy orm
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