当前位置:Gxlcms > 数据库问题 > Mysql数据库技术(四)

Mysql数据库技术(四)

时间:2021-07-01 10:21:17 帮助过:22人阅读

“001”课程比“002”课程成绩高的所有学生的学号;

select a.s_id from (select s_id,score from SC where C_ID=‘001‘) a,(select s_id,scorefrom SC where C_ID=‘002‘) b where a.score>b.score and a.s_id=b.s_id;

 

10.查询平均成绩大于60分的同学的学号和平均成绩;

select S_ID,avg(score) from sc group by S_ID having avg(score) >60;

 

11.查询所有同学的学号、姓名、选课数、总成绩;

select Student.S_ID,Student.Sname,count(SC.C_ID),sum(score) from Student left Outer join SC on Student.S_ID=SC.S_ID group by Student.S_ID,Sname

 

12.查询姓“李”的老师的个数;

select count(distinct(Tname)) from Teacher where Tname like ‘李%‘;

 

13.查询所有课程成绩小于60分的同学的学号、姓名;

select S_ID,Sname from Student where S_ID not in (select S.S_ID from Student AS S,SC where S.S_ID=SC.S_ID and score>60);

14.查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名;

select distinct S_ID,Sname from Student,SC where Student.S_ID=SC.S_ID and SC.C_ID in (select C_ID from SC where S_ID=‘1001‘);

 

Mysql数据库技术(四)

标签:技术   count   select   课程   mysql数据库   family   not   style   ike   

人气教程排行