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SQLServer复杂SQL逻辑实现

时间:2021-07-01 10:21:17 帮助过:36人阅读


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表A的SQL语句:

create table b(
  UserName nvarchar(200),Salary int
)
create table User_Salary (UserName nvarchar(200), Month nvarchar(20), Salary int)
go
insert into User_Salary (UserName,Month,Salary ) values('AAA','2010/12',1000)
insert into User_Salary (UserName,Month,Salary ) values('AAA','2011/01',2000)

insert into User_Salary (UserName,Month,Salary ) values('AAA','2011/02',3000)

insert into User_Salary (UserName,Month,Salary ) values('BBB','2010/12',2000)

insert into User_Salary (UserName,Month,Salary ) values('BBB','2011/01',2500)

insert into User_Salary (UserName,Month,Salary ) values('BBB','2011/02',2500)

insert into User_Salary (UserName,Month,Salary ) values('CCC','2013/12',5000)

insert into User_Salary (UserName,Month,Salary ) values('CCC','2013/04',4000)

insert into User_Salary (UserName,Month,Salary ) values('CCC','2013/02',3000)

二、SQL

SQLServer:

SELECT username,MONTH,Salary2 salary,SumSalary2 sumsalary FROM (
SELECT k.*,case when b.flag1=0 then -1 else b.flag1 end flag2
,case when B.flag1=1 and k.flag1<>1 then k.salary-(k.SumSalary-k.maxSalary) else k.salary end Salary2
,case when B.flag1=1 and k.flag1<>1 then k.maxSalary else k.SumSalary end SumSalary2   FROM   
(SELECT A.*,row_number() OVER(order by UserName,month desc) r  FROM 
(SELECT a.*,case when maxSalary>SumSalary then 1 when maxSalary=SumSalary then 0 else -1 end flag1 from(
select u.*
,(select SUM(salary) from User_Salary where User_Salary.Month>=u.month and User_Salary.UserName = u.userName) as SumSalary
,(select Salary from b where b.UserName = u.UserName) as maxSalary
from User_Salary u 
) a )A
) k 
LEFT JOIN 
(SELECT A.*,row_number() OVER(order by UserName,month desc) r FROM 
(SELECT a.*,case when maxSalary>SumSalary then 1 when maxSalary=SumSalary then 0 else -1 end flag1 from (
select u.*
,(select SUM(salary) from User_Salary where User_Salary.Month>=u.month and User_Salary.UserName = u.userName) as SumSalary
,(select Salary from b where b.UserName = u.UserName) as maxSalary
from User_Salary u 
) a )A
) B   
on k.R = B.R+1  
) a WHERE FLAG1=1 OR FLAG1 = 0 OR FLAG2 = 1

三、总结

主要还是对上一行下一行记录的获取上,也就是以前写的SQLServer的lead,lag的实现。如果SQLServer2010(好像是这版本),就有内置的lead,lag了,sql就简单了。

个人觉得这类SQL当做练手是不错的,但用着应用中复杂度就有点高了,应对对应用的业务和表结构做重新处理。

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SQLServer复杂SQL逻辑实现

标签:sqlserver   lead   leg   

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