Connector/c++ 查询Mysql，出现 can't fetch because not on result set 错误

出现原因可以看这里：http://stackoverflow.com/questions/17294611/sqlinvalidargumentexception-mysql-c

意思就是，每次读取 resultset里面的内容前，你都需要 调用一次 next()

像这样：

        // 输出结果    
        while(result->next())
        {
            int id = result->getInt("id");
            string name = result->getString("name");
            cout<<"testuser: "<< id <<" , "<<name<<endl;
        }                

Connector/c++ 查询Mysql，出现 can't fetch because not on result set 错误

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