oracle面试经典题

问题描述： 为管理岗位业务培训信息，建立3个表: 2 3 S (S#,SN,SD,SA) S#,SN,SD,SA 分别代表学号、学员姓名、所属单位、学员年龄 4 5 C (C#,CN ) C#,CN 分别代表课程编号、课程名称 6 7 SC ( S#,C#,G ) S#,C#,G 分别代表学号、所选修的课程编号、学习成绩 8 9 要求实现如下5个处理： 10 1. 使用标准SQL嵌套语句查询选修课程名称为’税收基础’的学员学号和姓名 11 --实现代码： 12 SELECT SN,SD FROM S 13 WHERE [S#] IN( 14 SELECT [S#] FROM C,SC 15 WHERE C.[C#]=SC.[C#] 16 AND CN=N‘税收基础‘) 17 18 19 2. 使用标准SQL嵌套语句查询选修课程编号为’C2’的学员姓名和所属单位 20 --实现代码： 21 SELECT S.SN,S.SD FROM S,SC 22 WHERE S.[S#]=SC.[S#] 23 AND SC.[C#]=‘C2‘ 24 25 3. 使用标准SQL嵌套语句查询不选修课程编号为’C5’的学员姓名和所属单位 26 --实现代码： 27 SELECT SN,SD FROM S 28 WHERE [S#] NOT IN( 29 SELECT [S#] FROM SC 30 WHERE [C#]=‘C5‘) 31 32 4. 使用标准SQL嵌套语句查询选修全部课程的学员姓名和所属单位 33 --实现代码： 34 SELECT SN,SD FROM S 35 WHERE [S#] IN( 36 SELECT [S#] FROM SC 37 RIGHT JOIN C ON SC.[C#]=C.[C#] 38 GROUP BY [S#] 39 HAVING COUNT(*)=COUNT(DISTINCT [S#])) 40 41 5. 查询选修了课程的学员人数 42 --实现代码： 43 SELECT 学员人数=COUNT(DISTINCT [S#]) FROM SC 44 45 6. 查询选修课程超过5门的学员学号和所属单位 46 --实现代码： 47 SELECT SN,SD FROM S 48 WHERE [S#] IN( 49 SELECT [S#] FROM SC 50 GROUP BY [S#] 51 HAVING COUNT(DISTINCT [C#])>5) 管理岗位业务培训信息

 

要求实现如下5个处理：

  1 sql面试题（学生表_课程表_成绩表_教师表）
  2 
  3 表架构
  4 
  5 Student(S#,Sname,Sage,Ssex) 学生表 
  6 Course(C#,Cname,T#) 课程表 
  7 SC(S#,C#,score) 成绩表 
  8 Teacher(T#,Tname) 教师表
  9 
 10 建表语句 
 11 
 12 CREATE TABLE student 
 13   ( 
 14      s#    INT, 
 15      sname nvarchar(32), 
 16      sage  INT, 
 17      ssex  nvarchar(8) 
 18   ) 
 19 
 20 CREATE TABLE course 
 21   ( 
 22      c#    INT, 
 23      cname nvarchar(32), 
 24      t#    INT 
 25   ) 
 26 
 27 CREATE TABLE sc 
 28   ( 
 29      s#    INT, 
 30      c#    INT, 
 31      score INT 
 32   ) 
 33 
 34 CREATE TABLE teacher 
 35   ( 
 36      t#    INT, 
 37      tname nvarchar(16) 
 38   )
 39 
 40 
 41 插入测试数据语句 
 42 insert into Student select 1,N‘刘一‘,18,N‘男‘ union all
 43  select 2,N‘钱二‘,19,N‘女‘ union all
 44  select 3,N‘张三‘,17,N‘男‘ union all
 45  select 4,N‘李四‘,18,N‘女‘ union all
 46  select 5,N‘王五‘,17,N‘男‘ union all
 47  select 6,N‘赵六‘,19,N‘女‘ 
 48  
 49  insert into Teacher select 1,N‘叶平‘ union all
 50  select 2,N‘贺高‘ union all
 51  select 3,N‘杨艳‘ union all
 52  select 4,N‘周磊‘
 53  
 54  insert into Course select 1,N‘语文‘,1 union all
 55  select 2,N‘数学‘,2 union all
 56  select 3,N‘英语‘,3 union all
 57  select 4,N‘物理‘,4
 58  
 59  insert into SC 
 60  select 1,1,56 union all 
 61  select 1,2,78 union all 
 62  select 1,3,67 union all 
 63  select 1,4,58 union all 
 64  select 2,1,79 union all 
 65  select 2,2,81 union all 
 66  select 2,3,92 union all 
 67  select 2,4,68 union all 
 68  select 3,1,91 union all 
 69  select 3,2,47 union all 
 70  select 3,3,88 union all 
 71  select 3,4,56 union all 
 72  select 4,2,88 union all 
 73  select 4,3,90 union all 
 74  select 4,4,93 union all 
 75  select 5,1,46 union all 
 76  select 5,3,78 union all 
 77  select 5,4,53 union all 
 78  select 6,1,35 union all 
 79  select 6,2,68 union all 
 80  select 6,4,71
 81 
 82 问题： 
 83 1、查询“001”课程比“002”课程成绩高的所有学生的学号； 
 84   select a.S# from (select s#,score from SC where C#=‘001‘) a,(select 
 85 
 86 s#,score 
 87   from SC where C#=‘002‘) b 
 88   where a.score>b.score and a.s#=b.s#; 
 89 2、查询平均成绩大于60分的同学的学号和平均成绩； 
 90     select S#,avg(score) 
 91     from sc 
 92     group by S# having avg(score) >60; 
 93 3、查询所有同学的学号、姓名、选课数、总成绩； 
 94   select Student.S#,Student.Sname,count(SC.C#),sum(score) 
 95   from Student left Outer join SC on Student.S#=SC.S# 
 96   group by Student.S#,Sname 
 97 4、查询姓“李”的老师的个数； 
 98   select count(distinct(Tname)) 
 99   from Teacher 
100   where Tname like ‘李%‘; 
101 5、查询没学过“叶平”老师课的同学的学号、姓名； 
102     select Student.S#,Student.Sname 
103     from Student  
104     where S# not in (select distinct( SC.S#) from SC,Course,Teacher 
105 
106 where  SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=‘叶
107 
108 平‘); 
109 6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名； 
110   select Student.S#,Student.Sname from Student,SC where 
111 
112 Student.S#=SC.S# and SC.C#=‘001‘and exists( Select * from SC as SC_2 
113 
114 where SC_2.S#=SC.S# and SC_2.C#=‘002‘); 
115 7、查询学过“叶平”老师所教的所有课的同学的学号、姓名； 
116   select S#,Sname 
117   from Student 
118   where S# in (select S# from SC ,Course ,Teacher where 
119 
120 SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=‘叶平‘ 
121 
122 group by S# having count(SC.C#)=(select count(C#) from Course,Teacher  
123 
124 where Teacher.T#=Course.T# and Tname=‘叶平‘)); 
125 8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、
126 
127 姓名； 
128   Select S#,Sname from (select Student.S#,Student.Sname,score ,(select 
129 
130 score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#=‘002‘) score2 
131   from Student,SC where Student.S#=SC.S# and C#=‘001‘) S_2 where 
132 
133 score2 <score; 
134 9、查询所有课程成绩小于60分的同学的学号、姓名； 
135   select S#,Sname 
136   from Student 
137   where S# not in (select S.S# from Student AS S,SC where S.S#=SC.S# 
138 
139 and score>60); 
140 10、查询没有学全所有课的同学的学号、姓名； 
141     select Student.S#,Student.Sname 
142     from Student,SC 
143     where Student.S#=SC.S# group by  Student.S#,Student.Sname having 
144 
145 count(C#) <(select count(C#) from Course); 
146 11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名； 
147     select distinct S#,Sname from Student,SC where Student.S#=SC.S# 
148 
149 and SC.C# in (select C# from SC where S#=‘1001‘); 
150 12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名； 
151     select distinct SC.S#,Sname 
152     from Student,SC 
153     where Student.S#=SC.S# and C# in (select C# from SC where 
154 
155 S#=‘001‘); 
156 13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩； 
157     update SC set score=(select avg(SC_2.score) 
158     from SC SC_2 
159     where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# 
160 
161 and Course.T#=Teacher.T# and Teacher.Tname=‘叶平‘); 
162 14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名； 
163     select S# from SC where C# in (select C# from SC where S#=‘1002‘) 
164     group by S# having count(*)=(select count(*) from SC where 
165 
166 S#=‘1002‘); 
167 15、删除学习“叶平”老师课的SC表记录； 
168     Delect SC 
169     from course ,Teacher  
170     where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname=‘叶平‘; 
171 16、向SC表中插入一些记录，这些记录要求符合以下条件：没有上过编号“003
172 
173 ”课程的同学学号、2、 
174     号课的平均成绩； 
175     Insert SC select S#,‘002‘,(Select avg(score) 
176     from SC where C#=‘002‘) from Student where S# not in (Select S# 
177 
178 from SC where C#=‘002‘); 
179 17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”
180 
181 三门的课程成绩，按如下形式显示： 学生ID,,数据库,企业管理,英语,有效课程
182 
183 数,有效平均分 
184     SELECT S# as 学生ID 
185         ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=‘004‘) AS 数据
186 
187 库 
188         ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=‘001‘) AS 企业
189 
190 管理 
191         ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=‘006‘) AS 英语 
192         ,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩 
193     FROM SC AS t 
194     GROUP BY S# 
195     ORDER BY avg(t.score)  
196 18、查询各科成绩最高和最低的分：以如下形式显示：课程ID，最高分，最低分 
197     SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分 
198     FROM SC L ,SC AS R 
199     WHERE L.C# = R.C# and 
200         L.score = (SELECT MAX(IL.score) 
201                       FROM SC AS IL,Student AS IM 
202                       WHERE L.C# = IL.C# and IM.S#=IL.S# 
203                       GROUP BY IL.C#) 
204         AND 
205         R.Score = (SELECT MIN(IR.score) 
206                       FROM SC AS IR 
207                       WHERE R.C# = IR.C# 
208                   GROUP BY IR.C# 
209                     ); 
210 自己写的:select c# ,max(score)as 最高分 ,min(score) as 最低分 from 
211 
212 dbo.sc  group by c#
213 19、按各科平均成绩从低到高和及格率的百分数从高到低顺序 
214     SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG
215 
216 (score),0) AS 平均成绩 
217         ,100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 
218 
219 END)/COUNT(*) AS 及格百分数 
220     FROM SC T,Course 
221     where t.C#=course.C# 
222     GROUP BY t.C# 
223     ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 
224 
225 END)/COUNT(*) DESC 
226 20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理（001）
227 
228 ，马克思（002），OO&UML （003），数据库（004） 
229     SELECT SUM(CASE WHEN C# =‘001‘ THEN score ELSE 0 END)/SUM(CASE C# 
230 
231 WHEN ‘001‘ THEN 1 ELSE 0 END) AS 企业管理平均分 
232         ,100 * SUM(CASE WHEN C# = ‘001‘ AND score >= 60 THEN 1 ELSE 0 
233 
234 END)/SUM(CASE WHEN C# = ‘001‘ THEN 1 ELSE 0 END) AS 企业管理及格百分数 
235         ,SUM(CASE WHEN C# = ‘002‘ THEN score EL