DB2行转列（多维度）

---------------建表 CREATE TABLE CUST_BANK_INFO ( CUST_ID VARCHAR(10), CUST_NAME VARCHAR(100), BANK_NO VARCHAR(100), BANK VARCHAR(100), MONEY_TYPE_NO VARCHAR(100), MONEY_TYPE VARCHAR(100), MONEY INT ); INSERT INTO CUST_BANK_INFO VALUES(‘C001‘,‘允贤‘,‘B01‘,‘中国银行‘,‘MT01‘,‘理财‘,10000); INSERT INTO CUST_BANK_INFO VALUES(‘C002‘,‘李四‘,‘B01‘,‘中国银行‘,‘MT02‘,‘贷款‘,20390); INSERT INTO CUST_BANK_INFO VALUES(‘C003‘,‘王五‘,‘B01‘,‘中国银行‘,‘MT03‘,‘存款‘,29301); INSERT INTO CUST_BANK_INFO VALUES(‘C004‘,‘陈六‘,‘B01‘,‘中国银行‘,‘MT04‘,‘教育储蓄‘,10000); INSERT INTO CUST_BANK_INFO VALUES(‘C001‘,‘允贤‘,‘B02‘,‘中国银行‘,‘MT01‘,‘理财‘,20000); INSERT INTO CUST_BANK_INFO VALUES(‘C005‘,‘JACK‘,‘B02‘,‘工商银行‘,‘MT05‘,‘理财‘,10001); INSERT INTO CUST_BANK_INFO VALUES(‘C006‘,‘王三‘,‘B02‘,‘工商银行‘,‘MT06‘,‘贷款‘,10002); INSERT INTO CUST_BANK_INFO VALUES(‘C007‘,‘刘六‘,‘B02‘,‘工商银行‘,‘MT07‘,‘存款‘,10003); INSERT INTO CUST_BANK_INFO VALUES(‘C008‘,‘郑七‘,‘B02‘,‘工商银行‘,‘MT08‘,‘教育储蓄‘,10004);

SELECT * FROM CUST_BANK_INFO

查询结果如下：

--DELETE FROM CUST_BANK_INFO
DROP TABLE Mapping;
CREATE TABLE Mapping
(
 CN_NAME VARCHAR(100),
 Code_L  VARCHAR(10),
 Code_N  VARCHAR(10)
)
INSERT INTO Mapping values(‘理财‘,‘MT01‘,‘BANK_01‘);
INSERT INTO Mapping values(‘理财‘,‘MT05‘,‘BANK_01‘);
INSERT INTO Mapping values(‘贷款‘,‘MT02‘,‘BANK_02‘);
INSERT INTO Mapping values(‘贷款‘,‘MT06‘,‘BANK_02‘);
INSERT INTO Mapping values(‘存款‘,‘MT03‘,‘BANK_03‘);
INSERT INTO Mapping values(‘存款‘,‘MT07‘,‘BANK_03‘);
INSERT INTO Mapping values(‘教育储蓄‘,‘MT04‘,‘BANK_04‘);
INSERT INTO Mapping values(‘教育储蓄‘,‘MT08‘,‘BANK_04‘);


    
SELECT CUST_ID,
       CUST_NAME,
       BANK_NO,
       BANK,
max(CASE WHEN B.Code_N=‘BANK_01‘ THEN MONEY ELSE ‘0‘ END) AS 理财,
max(CASE WHEN B.Code_N=‘BANK_02‘ THEN MONEY ELSE ‘0‘ END) AS 贷款,
max(CASE WHEN B.Code_N=‘BANK_03‘ THEN MONEY ELSE ‘0‘ END) AS 存款,
max(CASE WHEN B.Code_N=‘BANK_04‘ THEN MONEY ELSE ‘0‘ END) AS 教育储蓄
FROM CUST_BANK_INFO A
LEFT JOIN MAPPING B ON A.MONEY_TYPE_NO=B.Code_L
group by CUST_ID,CUST_NAME,BANK,BANK_NO

 

查询结果如下：

 

DB2行转列（多维度）

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