json返回数据库的时间格式为/Date(1477294037000)/，怎样在前台进行格式化转换

ChangeDateFormat(val) { if (val != null) { var date = new Date(parseInt(val.replace("/Date(", "").replace(")/", ""), 10)); //月份为0-11，所以+1，月份小于10时补个0 var month = date.getMonth() + 1 < 10 ? "0" + (date.getMonth() + 1) : date.getMonth() + 1; var currentDate = date.getDate() < 10 ? "0" + date.getDate() : date.getDate(); return date.getFullYear() + "-" + month + "-" + currentDate; } return ""; }

 

方法二：

---

<span style="color: #0000ff">var</span> str = ‘/Date(1333245600000+0800)/‘<span style="color: #000000">;
 
</span><span style="color: #0000ff">function</span><span style="color: #000000"> data_string(str) {
    </span><span style="color: #0000ff">var</span> d = eval(‘new ‘ + str.substr(1, str.length - 2<span style="color: #000000">));
    </span><span style="color: #0000ff">var</span> ar_date = [d.getFullYear(), d.getMonth() + 1<span style="color: #000000">, d.getDate()];
    </span><span style="color: #0000ff">for</span> (<span style="color: #0000ff">var</span> i = 0; i < ar_date.length; i ++) ar_date[i] =<span style="color: #000000"> dFormat(ar_date[i]);
    </span><span style="color: #0000ff">return</span> ar_date.join(‘-‘<span style="color: #000000">);
     
    </span><span style="color: #0000ff">function</span> dFormat(i) { <span style="color: #0000ff">return</span> i < 10 ? "0" +<span style="color: #000000"> i.toString() : i; }
}<br>
alert(data_string(str));</span>

 

更多方法请查看：http://bbs.csdn.net/topics/390050932

json返回数据库的时间格式为/Date(1477294037000)/，怎样在前台进行格式化转换

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