Leetcode 178. Rank Scores (Database)

 排序2. 相同分数排名相同，排名第n名表示前面有n-1个人，而不是n-1个分数。

Score  Rank

100     1

  99     2

  99     2

  98     4

  90     5

# Write your MySQL query statement below
select S1.Score, (
select count(Score) + 1 
from Scores S2
where S1.Score < S2.Score ) 
as Rank 
from Scores S1 order by Score desc

 排序3. 相同分数排名相同，第n名表示前面有n-1个分数。

 Score  Rank

100     1

  99     2

  99     2

  98     3

  90     4

# Write your MySQL query statement below
select s.Score, count(distinct t.Score) Rank
from Scores s join Scores t on s.Score <= t.Score    #join 和 inner join是
group by s.Id
order by s.Score desc;

Leetcode 178. Rank Scores (Database)

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