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mysql function

时间:2021-07-01 10:21:17 帮助过:18人阅读

Map1" type="com.young.Model"> <id column="id" jdbcType="BIGINT" property="id" /> ...... <collection property="treatmentMethodList" column="id" ofType="com.young.Treatment"> <result column="name" jdbcType="VARCHAR" property="name" /> </collection>

column 代表数据库字段,property代表对象中的属性,两者之间为映射关系.collection中的result为查询出的关联部分的属性,一对多,多合并为集合,一还是一,结果中一不会应为一对多而出现重复.

select
        mmc.id ,mmc...,mtt.name
    from
        mml_card mmc
    left join 
        mt_treatment mtt
    on mmc.id = mtt.medical_card_id

2. 按类型分组查询某个条件的数量

select
            tumour_kind_name tumourKindName,COUNT(DISTINCT patient_id) shouldFollow
        from 
            mss_medical_card mmc
        WHERE 
            YEAR(DATE_ADD(mmc.confirmed_date,INTERVAL mmc.cycle day)) = YEAR(‘2017-06-01 20:14:12‘)
        and 
            is_death = 0
        
        group by tumourKindName;

 

mysql function

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