时间:2021-07-01 10:21:17 帮助过:65人阅读
SET DATEFIRST 1 --定义日期周一开始
三:直接写一个函数,每次调用一下就可以了
SELECT @@DATEFIRST --7 SELECT DATENAME(WEEK,‘2013-12-31‘) AS WeekName -- 53 SELECT DATENAME(WEEK,‘2014-01-01‘) AS WeekName -- 1 SELECT DATENAME(WEEK,‘2014-01-05‘) AS WeekName -- 2
代码:
1.创建表:
IF OBJECT_ID(‘DimDateStartWithMonday‘,‘U‘) IS NOT NULL DROP TABLE DimDateStartWithMonday GO CREATE TABLE DimDateStartWithMonday ( DateKey INT PRIMARY KEY, FullDate DATE NOT NULL, [DateName] NVARCHAR(20), DayNumberOfWeek TINYINT NOT NULL, DayNameOfWeek NVARCHAR(10) NOT NULL, DayNumberOfMonth TINYINT NOT NULL, DayNumberOfYear SMALLINT NOT NULL, WeekNumberOfYear TINYINT NOT NULL, EnglishMonthName NVARCHAR(10) NOT NULL, MonthNumberOfYear TINYINT NOT NULL, CalendarQuarter TINYINT NOT NULL, CalendarSemester TINYINT NOT NULL, CalendarYear SMALLINT NOT NULL )
2.插入值
DECLARE @StartDate DATETIME DECLARE @EndDate DATETIME SELECT @StartDate = ‘2001-01-01‘, @EndDate = ‘2035-12-31‘ WHILE(@StartDate<+@EndDate) BEGIN INSERT INTO DimDateStartWithMonday ( DateKey, FullDate, [DateName], DayNumberOfWeek, DayNameOfWeek, DayNumberOfMonth, DayNumberOfYear, WeekNumberOfYear, EnglishMonthName, MonthNumberOfYear, CalendarQuarter, CalendarSemester, CalendarYear ) SELECT CAST(CONVERT(VARCHAR(8),@StartDate,112) AS INT) AS DateKey, CONVERT(VARCHAR(10), @StartDate,20) AS FullDate, CONVERT(VARCHAR(20), @StartDate,106) AS [DateName], DATEPART(DW,@StartDate) AS DayNumberOfWeek, DATENAME(DW,@StartDate) AS DayNameOfWeek, DATENAME(DD,@StartDate) AS [DayOfMonth], DATENAME(DY,@StartDate) AS [DayOfYear], DATEPART(WW,@StartDate) AS WeekNumberOfYear, DATENAME(MM,@StartDate) AS EnglishMonthName, DATEPART(MM,@StartDate) AS MonthNumberOfYear, DATEPART(QQ,@StartDate) AS CalendarQuarter, CASE WHEN DATEPART(MM,@StartDate) BETWEEN 1 AND 6 THEN 1 ELSE 2 END AS CalendarSemester, DATEPART(YY,@StartDate) AS CalendarYear SET @StartDate = @StartDate + 1 END
3.自定义函数
IF OBJECT_ID(‘ETLWORK_GETWEEKNUMBER‘,‘FN‘) IS NOT NULL DROP FUNCTION ETLWORK_GETWEEKNUMBER GO CREATE FUNCTION ETLWORK_GETWEEKNUMBER(@DATE DATETIME) RETURNS INTEGER AS BEGIN DECLARE @FIRST_DATE_OF_YEAR DATETIME = DATEADD(YYYY,DATEDIFF(YYYY,0,@DATE),0) DECLARE @WEEK_NUMBER INTEGER -- 如果当前时间是当前年的第一天 IF @DATE = @FIRST_DATE_OF_YEAR SET @WEEK_NUMBER = 1 -- 星期天是年第一天的情况 ELSE IF (DATEPART(WEEKDAY,@DATE) = 1 AND DATEDIFF(DAYOFYEAR,@FIRST_DATE_OF_YEAR,@DATE)/7 + 1 = DATEPART(WEEK,@DATE)) SET @WEEK_NUMBER = DATEPART(WEEK,@DATE) -- 星期天不是年第一天的情况 ELSE IF (DATEPART(WEEKDAY,@DATE) = 1 AND DATEDIFF(DAYOFYEAR,@FIRST_DATE_OF_YEAR,@DATE)/7 + 1 <> DATEPART(WEEK,@DATE)) SET @WEEK_NUMBER = DATEPART(WEEK,@DATE) - 1 -- 如果当前天的上一个周日小于年第一天 ELSE IF DATEADD(DAY,-1,DATEADD(WK,DATEDIFF(WK,0,@DATE),0)) < @FIRST_DATE_OF_YEAR SET @WEEK_NUMBER = 1 -- 当前天前面的一个周日正好是以周日为开始年的 7 倍的天数 ELSE IF DATEDIFF(DAYOFYEAR,@FIRST_DATE_OF_YEAR,DATEADD(DAY,-1,DATEADD(WK,DATEDIFF(WK,0,@DATE),0) ))/7 + 1 = DATEPART(WEEK,@DATE) SET @WEEK_NUMBER = DATEPART(WEEK,@DATE) + 1 ELSE SET @WEEK_NUMBER = DATEPART(WEEK,@DATE) RETURN @WEEK_NUMBER END
测试:
DECLARE @DATE DATETIME = ‘2017-01-02‘ DECLARE @FIRST_DATE_OF_YEAR DATETIME = DATEADD(YYYY,DATEDIFF(YYYY,0,@DATE),0) SELECT DATEPART(WEEK,@DATE), -- 一年中的周数,默认以周日开始 DATEADD(WK,DATEDIFF(WK,0,@DATE),0), -- 当前周的周一,默认从周日开始,但是仍然找周一 DATEADD(DAY,-1,DATEADD(WK,DATEDIFF(WK,0,@DATE),0)), -- 当前周先找周一,然后往前一天找到周日 DATEDIFF(DAYOFYEAR,@FIRST_DATE_OF_YEAR,DATEADD(DAY,-1,DATEADD(WK,DATEDIFF(WK,0,@DATE),0))), -- 当前天离年第一天的间隔 DATEDIFF(DAYOFYEAR,@FIRST_DATE_OF_YEAR,DATEADD(DAY,-1,DATEADD(WK,DATEDIFF(WK,0,@DATE),0) ))/7 + 1 -- 按天计算的周数
SqlServer中 SET DATEFIRST更改
标签:ast 定义函数 style tiny 默认 sel 需要 first cal