sql中经度维度计算距离
时间：2021-07-01 10:21:17
帮助过：27人阅读
@LatBegin 纬度A(33.8703596)--
--@LngBegin 经度A(-117.9242966)--
--@LatEnd 纬度B(34.0392283)--
--@LngEnd 经度B(-117.8367681)--
CREATE FUNCTION [dbo].
[fnGetDistance](
@LatBegin REAL,
@LngBegin REAL,
@LatEnd REAL,
@LngEnd REAL)
RETURNS FLOAT
AS
BEGIN
--距离(千米)
DECLARE @Distance REAL
--距离(英里)--
DECLARE @Edistance REAL
DECLARE @EARTH_RADIUS REAL
DECLARE @MI REAL
SET @EARTH_RADIUS = 6378.137 --地球半径(千米)--
Set @MI=0.6213712 --1千米(km)=0.6213712英里(mi)
DECLARE @RadLatBegin REAL,
@RadLatEnd REAL,
@RadLatDiff REAL,
@RadLngDiff REAL
SET @RadLatBegin = @LatBegin *PI()
/180.0
SET @RadLatEnd = @LatEnd *PI()
/180.0
SET @RadLatDiff = @RadLatBegin - @RadLatEnd
SET @RadLngDiff = @LngBegin *PI()
/180.0 - @LngEnd *PI()
/180.0
SET @Distance = 2 *ASIN(
SQRT(
POWER(
SIN(
@RadLatDiff/2),
2)
+COS(
@RadLatBegin)
*COS(
@RadLatEnd)
*POWER(
SIN(
@RadLngDiff/2),
2)))
SET @Distance = @Distance * @EARTH_RADIUS
SET @Distance = Round(
@Distance * 10000,
1)
/ 10000 --千米--
SET @Edistance= @Distance * @MI --英里--
RETURN @Edistance
END
------------------------------------------删除方法--------------------------------------------------------------------
drop function dbo.fnGetDistance
------------------------------------------调用方法--------------------------------------------------------------------
select dbo.fnGetDistance(33.8703596,-117.9242966,34.0392283,-117.8367681)
sql中经度维度计算距离
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