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oracle练习

时间:2021-07-01 10:21:17 帮助过:9人阅读


select * from(select e.ename from emp e join dept d on(e.deptno = d.deptno)where d.loc=‘CHICAGO‘ order by sal desc) where rownum=1;

- 查询每个部门下有多少员工
select dname,count(ename) from dept d left outer join emp e on d.deptno=e.deptno group by dname
- 查询除去 salesman 所有平均工资超过 1500 的部门
select d.dname,avg(e.sal+nvl(e.comm,0)) from dept d join emp e on d.deptno=e.deptno where job!=‘salesman‘ group by dname having avg(e.sal+nvl(e.comm,0))>1500;

- 查询在 new york 工作的所有员工的姓名,部门名称和工资信息
select ename,d.dname,sal from emp e join dept d on d.deptno=e.deptno where d.loc=‘NEW YORK‘;
- 查询姓名为 King 的员工的编号,名称跟部门
select empno,ename,d.dname from emp e join dept d on d.deptno=e.deptno where e.ename=‘KING‘
- 查询各种工作的最低工资
select job,min(sal) from emp group by job;
- 查询工龄大于10年的所有员工信息
select * from emp where (months_between(sysdate,hiredate)/12)>10;

- 查询每个部门员工数量,平均工资和平均工作年限
select dname,count(ename),avg(sal+nvl(comm,0)),avg(to_char(hiredate,‘yyyy‘)) from dept d left outer join emp e on d.deptno = e.deptno group by dname;

- 统计各部门每个工种的人数,平均工资。
select dname,count(ename),avg(sal+nvl(comm,0)) from dept d left join emp e on e.deptno=d.deptno group by dname;

oracle练习

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