时间:2021-07-01 10:21:17 帮助过:23人阅读
create table emp (
empno int(10) primary key,
ename varchar(20),
deptno int(10),
sal decimal(10,2)
);
create table department (
deptno int(10) primary key,
dname varchar(20),
manager varchar(20)
);
根据题目的关键字自行构建测试数据(比较重要)
(1)向职工表中插入行(‘025’,‘王芳’,‘03’,1000)
insert into emp values(‘025‘, ‘王芳‘, ‘03‘, ‘1000‘);
(2)从职工表中删除人事处的所有员工
delete from emp where deptno = (select deptno from department where dname = ‘人事处‘);
(3)将职工号为‘001’的员工工资改为700元钱
update emp set sal = ‘700‘ where empno = ‘001‘;
(4)查询人事处的员工最高工资
select max(sal) from emp where deptno = (select deptno from department where dname = ‘人事处‘);
(5)查询“王芳”所在部门的部门主任
select manager from department where deptno = (select deptno from emp where ename = ‘王芳‘);
(6)查询与“王芳”在同一部门的其它员工信息
select * from emp where deptno = (select deptno from emp where ename = ‘王芳‘) and ename not like ‘王芳‘;
(7)建立公司所有部门的公共视图——部门职工视图
create view dept_sta_view(empno, ename, deptno, sal, dname, mgr) as select a.empno, a.ename, a.deptno, a.sal, b.dname, b.manager from emp a, department b where a.deptno = b.deptno;
(8)从部门职工视图中查询财务处员工工资高于800元的员工信息
select * from dept_sta_view where sal > ‘800‘ and dname = ‘财务处‘;
mysql练习02
标签:art dna 视图 style view span 系统 table max