时间:2021-07-01 10:21:17 帮助过:110人阅读
Alternatively, create an own implementation of
JdbcDaoSupport
class, and do whatever you want. Dive inside the source code ofJdbcDaoSupport
, it’s just a simple helper class to create ajdbcTemplate
.
我创建了一个自己的类,扩展了JdbcDaoSupport类:
- package demo1;
- import javax.annotation.PostConstruct;
- import javax.sql.DataSource;
- import org.springframework.beans.factory.annotation.Autowired;
- import org.springframework.jdbc.core.support.JdbcDaoSupport;
- public class JdbcDaoSupportExtend extends JdbcDaoSupport {
- @Autowired
- private DataSource dataSource;
- @PostConstruct
- public void initialize() {
- setDataSource(dataSource);
- }
- }
在自己的Dao中继承了这个自己扩展的类:
- package demo1;
- import org.springframework.stereotype.Repository;
- @Repository(value = "userDao")
- public class UserDaoImpl extends JdbcDaoSupportExtend implements UserDaoI {
- @Override
- public void outMoney(Integer id, Double money) {
- getJdbcTemplate().update("update user set money = money - ? where id = ?", money, id);
- }
- @Override
- public void inMoney(Integer id, Double money) {
- getJdbcTemplate().update("update user set money = money + ? where id = ?", money, id);
- }
- }
解决Spring框架的Dao层改用@Repository注解,无法使用JdbcDaoSupport的问题
标签:integer imp upd you http dao template 创建 core