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mysql互换表中两列数据方法

时间:2021-07-01 10:21:17 帮助过:4人阅读

 

mysql> select * from product;
+----+--------+----------------+--------+
| id | name   | original_price | price  |
+----+--------+----------------+--------+
|  1 | 雪糕   |           5.00 |   3.50 |
|  2 | 鲜花   |          18.00 |  15.00 |
|  3 | 甜点   |          25.00 |  12.50 |
|  4 | 玩具   |          55.00 |  45.00 |
|  5 | 钱包   |         285.00 | 195.00 |
+----+--------+----------------+--------+
5 rows in set (0.00 sec)

 

 

2.互换original_price与price的值

新手可能会使用以下方法进行互换

update product set original_price=price,price=original_price;
  • 1

但这样执行的结果只会使original_price与price的值都是price的值,因为update有顺序的, 
先执行original_price=price , original_price的值已经更新为price, 
然后执行price=original_price,这里相当于没有更新。

执行结果:

mysql> select * from product;
+----+--------+----------------+--------+
| id | name   | original_price | price  |
+----+--------+----------------+--------+
|  1 | 雪糕   |           5.00 |   3.50 |
|  2 | 鲜花   |          18.00 |  15.00 |
|  3 | 甜点   |          25.00 |  12.50 |
|  4 | 玩具   |          55.00 |  45.00 |
|  5 | 钱包   |         285.00 | 195.00 |
+----+--------+----------------+--------+
5 rows in set (0.00 sec)

mysql> update product set original_price=price,price=original_price;
Query OK, 5 rows affected (0.00 sec)
Rows matched: 5  Changed: 5  Warnings: 0

mysql> select * from product;
+----+--------+----------------+--------+
| id | name   | original_price | price  |
+----+--------+----------------+--------+
|  1 | 雪糕   |           3.50 |   3.50 |
|  2 | 鲜花   |          15.00 |  15.00 |
|  3 | 甜点   |          12.50 |  12.50 |
|  4 | 玩具   |          45.00 |  45.00 |
|  5 | 钱包   |         195.00 | 195.00 |
+----+--------+----------------+--------+
5 rows in set (0.00 sec)



正确的互换方法如下:

update product as a, product as b set a.original_price=b.price, a.price=b.original_price where a.id=b.id;
  • 1

执行结果:

mysql> select * from product;
+----+--------+----------------+--------+
| id | name   | original_price | price  |
+----+--------+----------------+--------+
|  1 | 雪糕   |           5.00 |   3.50 |
|  2 | 鲜花   |          18.00 |  15.00 |
|  3 | 甜点   |          25.00 |  12.50 |
|  4 | 玩具   |          55.00 |  45.00 |
|  5 | 钱包   |         285.00 | 195.00 |
+----+--------+----------------+--------+
5 rows in set (0.00 sec)

mysql> update product as a, product as b set a.original_price=b.price, a.price=b.original_price where a.id=b.id;
Query OK, 5 rows affected (0.01 sec)
Rows matched: 5  Changed: 5  Warnings: 0

mysql> select * from product;
+----+--------+----------------+--------+
| id | name   | original_price | price  |
+----+--------+----------------+--------+
|  1 | 雪糕   |           3.50 |   5.00 |
|  2 | 鲜花   |          15.00 |  18.00 |
|  3 | 甜点   |          12.50 |  25.00 |
|  4 | 玩具   |          45.00 |  55.00 |
|  5 | 钱包   |         195.00 | 285.00 |
+----+--------+----------------+--------+
5 rows in set (0.00 sec)

最后我用
update product as a, product as b set a.original_price=b.price, a.price=b.original_price where a.id=b.id;

http://blog.csdn.net/fdipzone/article/details/50864196

 

mysql互换表中两列数据方法

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