时间:2021-07-01 10:21:17 帮助过:8人阅读
with cr as ( select CountryRegionCode from person.CountryRegion where Name like ‘C%‘ ) select * from person.StateProvince where CountryRegionCode in (select * from cr)
其中cr是一个公用表表达式,该表达式在使用上与表变量类似,只是SQL Server 2005在处理公用表表达式的方式上有所不同。
在使用CTE时应注意如下几点:
1. CTE后面必须直接跟使用CTE的SQL语句(如select、insert、update等),否则,CTE将失效。如下面的SQL语句将无法正常使用CTE:
with cr as ( select CountryRegionCode from person.CountryRegion where Name like ‘C%‘ ) select * from person.CountryRegion -- 应将这条SQL语句去掉 -- 使用CTE的SQL语句应紧跟在相关的CTE后面 -- select * from person.StateProvince where CountryRegionCode in (select * from cr)
2. CTE后面也可以跟其他的CTE,但只能使用一个with,多个CTE中间用逗号(,)分隔,如下面的SQL语句所示:
with cte1 as ( select * from table1 where name like ‘abc%‘ ), cte2 as ( select * from table2 where id > 20 ), cte3 as ( select * from table3 where price < 100 ) select a.* from cte1 a, cte2 b, cte3 c where a.id = b.id and a.id = c.id
3. 如果CTE的表达式名称与某个数据表或视图重名,则紧跟在该CTE后面的SQL语句使用的仍然是CTE,当然,后面的SQL语句使用的就是数据表或视图了,如下面的SQL语句所示:
-- table1是一个实际存在的表 with table1 as ( select * from persons where age < 30 ) select * from table1 -- 使用了名为table1的公共表表达式 select * from table1 -- 使用了名为table1的数据表
4. CTE 可以引用自身,也可以引用在同一 WITH 子句中预先定义的 CTE。不允许前向引用。
--使用递归公用表表达式显示递归的多个级别 WITH DirectReports(ManagerID, EmployeeID, EmployeeLevel) AS ( SELECT ManagerID, EmployeeID, 0 AS EmployeeLevel FROM HumanResources.Employee WHERE ManagerID IS NULL UNION ALL SELECT e.ManagerID, e.EmployeeID, EmployeeLevel + 1 FROM HumanResources.Employee e INNER JOIN DirectReports d ON e.ManagerID = d.EmployeeID ) SELECT ManagerID, EmployeeID, EmployeeLevel FROM DirectReports ; --使用递归公用表表达式显示递归的两个级别 WITH DirectReports(ManagerID, EmployeeID, EmployeeLevel) AS ( SELECT ManagerID, EmployeeID, 0 AS EmployeeLevel FROM HumanResources.Employee WHERE ManagerID IS NULL UNION ALL SELECT e.ManagerID, e.EmployeeID, EmployeeLevel + 1 FROM HumanResources.Employee e INNER JOIN DirectReports d ON e.ManagerID = d.EmployeeID ) SELECT ManagerID, EmployeeID, EmployeeLevel FROM DirectReports WHERE EmployeeLevel <= 2 --使用递归公用表表达式显示层次列表 WITH DirectReports(Name, Title, EmployeeID, EmployeeLevel, Sort) AS (SELECT CONVERT(varchar(255), c.FirstName + ‘ ‘ + c.LastName), e.Title, e.EmployeeID, 1, CONVERT(varchar(255), c.FirstName + ‘ ‘ + c.LastName) FROM HumanResources.Employee AS e JOIN Person.Contact AS c ON e.ContactID = c.ContactID WHERE e.ManagerID IS NULL UNION ALL SELECT CONVERT(varchar(255), REPLICATE (‘| ‘ , EmployeeLevel) + c.FirstName + ‘ ‘ + c.LastName), e.Title, e.EmployeeID, EmployeeLevel + 1, CONVERT (varchar(255), RTRIM(Sort) + ‘| ‘ + FirstName + ‘ ‘ + LastName) FROM HumanResources.Employee as e JOIN Person.Contact AS c ON e.ContactID = c.ContactID JOIN DirectReports AS d ON e.ManagerID = d.EmployeeID ) SELECT EmployeeID, Name, Title, EmployeeLevel FROM DirectReports ORDER BY Sort --使用 MAXRECURSION 取消一条语句 --可以使用 MAXRECURSION 来防止不合理的递归 CTE 进入无限循环。以下示例特意创建了一个无限循环,然后使用 MAXRECURSION 提示将递归级别限制为两级 WITH cte (EmployeeID, ManagerID, Title) as ( SELECT EmployeeID, ManagerID, Title FROM HumanResources.Employee WHERE ManagerID IS NOT NULL UNION ALL SELECT cte.EmployeeID, cte.ManagerID, cte.Title FROM cte JOIN HumanResources.Employee AS e ON cte.ManagerID = e.EmployeeID ) --Uses MAXRECURSION to limit the recursive levels to 2 SELECT EmployeeID, ManagerID, Title FROM cte OPTION (MAXRECURSION 2) --在更正代码错误之后,就不再需要 MAXRECURSION。以下示例显示了更正后的代码 WITH cte (EmployeeID, ManagerID, Title) AS ( SELECT EmployeeID, ManagerID, Title FROM HumanResources.Employee WHERE ManagerID IS NOT NULL UNION ALL SELECT e.EmployeeID, e.ManagerID, e.Title FROM HumanResources.Employee AS e JOIN cte ON e.ManagerID = cte.EmployeeID ) SELECT EmployeeID, ManagerID, Title FROM cte
5. 不能在 CTE_query_definition 中使用以下子句:
(1)COMPUTE 或 COMPUTE BY
(2)ORDER BY(除非指定了 TOP 子句)
(3)INTO
(4)带有查询提示的 OPTION 子句
(5)FOR XML
(6)FOR BROWSE
6. 如果将 CTE 用在属于批处理的一部分的语句中,那么在它之前的语句必须以分号结尾,如下面的SQL所示:
declare @s nvarchar(3) set @s = ‘C%‘ ; -- 必须加分号 with t_tree as ( select CountryRegionCode from person.CountryRegion where Name like @s ) select * from person.StateProvince where CountryRegionCode in (select * from t_tree)
SQL With As 用法
标签:问题 无限循环 名称 指定 速度 where null 定义 toolbar