时间:2021-07-01 10:21:17 帮助过:9人阅读
1.from
先选择一个表,构成一个结果集。
2.where
对结果集进行筛选,筛选出需要的信息形成新的结果集。
3.group by
对新的结果集分组。
4.having
筛选出想要的分组。
5.select
选择列。
6.order by
当所有的条件都弄完了。最后排序。
explain select users.`mobile_num`, concat(users.`lastName` ,users.`firstName`) as userName, users.`company`,
(case `users`.`idPhotoCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `idPhotoCheckStatus`,
(case `users`.`driverLicenseCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `driverLicenseCheckStatus`,
(case `users`.`companyCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `companyCheckStatus`,
(case `users`.`unionCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `unionCheckStatus`,
ptrip_num, dtrip_num
from users
left join
(select count(passenger_trip.id) as ptrip_num, passenger_trip.`userId` from passenger_trip where passenger_trip.status != ‘cancel‘ group by passenger_trip.`userId` ) as ptrip
on ptrip.userId = users.id
left join
(select count(driver_trip.id) as dtrip_num, driver_trip.`userId` from driver_trip where driver_trip.status != ‘cancel‘ group by driver_trip.`userId` ) as dtrip
on dtrip.userId = users.id
where company != ‘上海狮博实业投资有限公司‘ and company != ‘88共享‘
explain select users.`mobile_num`, concat(users.`lastName` ,users.`firstName`) as userName, users.`company`,
(case `users`.`idPhotoCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `idPhotoCheckStatus`,
(case `users`.`driverLicenseCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `driverLicenseCheckStatus`,
(case `users`.`companyCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `companyCheckStatus`,
(case `users`.`unionCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `unionCheckStatus`,
(select count(passenger_trip.id) from passenger_trip where passenger_trip.userId = users.id and passenger_trip.status != ‘cancel‘) as ptrip_num,
(select count(driver_trip.id) from driver_trip where driver_trip.userId = users.id and driver_trip.status != ‘cancel‘) as dtrip_num
from users
where company != ‘上海狮博实业投资有限公司‘ and company != ‘88共享‘
explain select users.`mobile_num`, concat(users.`lastName` ,users.`firstName`) as userName, users.`company`,
(case `users`.`idPhotoCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `idPhotoCheckStatus`,
(case `users`.`driverLicenseCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `driverLicenseCheckStatus`,
(case `users`.`companyCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `companyCheckStatus`,
(case `users`.`unionCheckStatus` when ‘2‘ then ‘已认证‘ when ‘3‘ then ‘已驳回‘ else ‘待认证‘ end) as `unionCheckStatus`,
count(passenger_trip.id) as ptrip_num
from users
left join passenger_trip on passenger_trip.userId = users.id and passenger_trip.status != ‘cancel‘
left join driver_trip on driver_trip.`userId`=users.`id` and driver_trip.`status` != ‘cancel‘
where company != ‘上海狮博实业投资有限公司‘ and company != ‘88共享‘
SQL关联查询 直接join 和子查询的区别
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