MySQL_项目7: 各部门工资最高的员工（难度：中等）

创建employee表 CREATE TABLE employee ( id int(11) NOT NULL, name varchar(50) NOT NULL, salary decimal(10,2) NOT NULL DEFAULT ‘0.00‘, departmentid int(11) NOT NULL, PRIMARY KEY (`id`)); -- 插入数据 INSERT INTO `employee` VALUES (‘1‘, ‘Joe‘, ‘70000.00‘, ‘1‘); INSERT INTO `employee` VALUES (‘2‘, ‘Herry‘, ‘80000.00‘, ‘2‘); INSERT INTO `employee` VALUES (‘3‘, ‘Sam‘, ‘60000.00‘, ‘2‘); INSERT INTO `employee` VALUES (‘4‘, ‘Max‘, ‘90000.00‘, ‘1‘); INSERT INTO `employee` VALUES (‘5‘, ‘Janet‘, ‘69000.00‘, ‘1‘); INSERT INTO `employee` VALUES (‘6‘, ‘Randy‘, ‘85000.00‘, ‘1‘); INSERT INTO `employee` VALUES (‘7‘, ‘sherry‘, ‘90000.00‘, ‘1‘); INSERT INTO `employee` VALUES (‘8‘, ‘haha‘, ‘80000.00‘, ‘2‘); INSERT INTO `employee` VALUES (‘9‘, ‘Abbo‘, ‘80800.00‘, ‘3‘);

 

创建Department 表，包含公司所有部门的信息。

+----+----------+

| Id | Name |

+----+----------+

| 1 | IT |

| 2 | Sales |

+----+----------+

-- 创建department表
CREATE TABLE department (
id int(11) NOT NULL,
name varchar(100) NOT NULL,
PRIMARY KEY (`id`));

-- 插入数据
INSERT INTO `department` VALUES (‘1‘, ‘IT‘);
INSERT INTO `department` VALUES (‘2‘, ‘Sales‘);
INSERT INTO `department` VALUES (‘3‘, ‘customs‘);

 

编写一个 SQL 查询，找出每个部门工资最高的员工。例如，根据上述给定的表格，Max 在 IT 部门有最高工资，Henry 在 Sales 部门有最高工资。

+------------+----------+--------+

| Department | Employee | Salary |

+------------+----------+--------+

| IT | Max | 90000 |

| Sales | Henry | 80000 |

+------------+----------+--------+

 

注意点：需要考虑同部门最高工资有多个人的情况

SELECT e.*,t.name department,t.maxsal
FROM employee e
INNER JOIN
                    (SELECT e.departmentid,d.name,MAX(salary) maxsal
                    FROM employee e
                    INNER JOIN department d
                    on e.departmentid = d.id
                    GROUP BY e.departmentid,d.name) t
on e.departmentid = t.departmentid

WHERE e.salary=t.maxsal

 

MySQL_项目7: 各部门工资最高的员工（难度：中等）

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