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Oracle根据连续性日期的重复数据取最大或最小值日期

时间：2021-07-01 10:21:17 帮助过：87人阅读

INSERT INTO TB SELECT DATE‘2010-01-01‘,‘8%‘,‘10%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2011-01-01‘,‘5%‘,‘7%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2012-01-01‘,‘5%‘,‘7%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2012-10-31‘,‘5%‘,‘6%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2013-01-01‘,‘5%‘,‘6%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2013-03-31‘,‘8%‘,‘9%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2013-09-01‘,‘8%‘,‘10%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2014-01-01‘,‘8%‘,‘9%‘ FROM DUAL;
INSERT INTO TB SELECT DATE‘2015-01-01‘,‘6%‘,‘9%‘ FROM DUAL;
SELECT MIN(PB_DATE)START_DATE,MAX(END_DATE)END_DATE,SAVE_RATE,LEN_RATE FROM(
SELECT PB_DATE,LEAD(PB_DATE,1,DATE‘9999-12-31‘)OVER(ORDER BY PB_DATE)-1 AS END_DATE,SAVE_RATE,LEN_RATE FROM TB)
GROUP BY SAVE_RATE,LEN_RATE;
SELECT T.*,MAX(PB_DATE)KEEP(DENSE_RANK LAST ORDER BY SAVE_RATE,LEN_RATE)OVER(PARTITION BY SAVE_RATE,LEN_RATE)AS RN FROM TB T ORDER BY 1 ;
SELECT * FROM TB;*/
/* Formatted on 2019/9/24 12:29:14 (QP5 v5.227.12220.39754) */
/* Formatted on 2019/9/24 12:41:16 (QP5 v5.227.12220.39754) */

实现代码，以上代码是造数脚本：
WITH TMP
AS ( SELECT PB_DATE,
SAVE_RATE,
LEN_RATE,
LEAD (PB_DATE, 1, DATE ‘9999-12-31‘) OVER (ORDER BY PB_DATE)
NEXT_DATE,
LAG (PB_DATE, 1, PB_DATE) OVER (ORDER BY PB_DATE) PRE_DATE,
LEAD (SAVE_RATE) OVER (ORDER BY PB_DATE) NEXT_SAVE,
LAG (SAVE_RATE) OVER (ORDER BY PB_DATE) PRE_SAVE,
LEAD (LEN_RATE) OVER (ORDER BY PB_DATE) NEXT_LEN,
LAG (LEN_RATE) OVER (ORDER BY PB_DATE) PRE_LEN
FROM TB
ORDER BY PB_DATE, SAVE_RATE, LEN_RATE),
TMP2
AS ( SELECT MAX (T.PB_DATE) AS PB_DATE, T.SAVE_RATE, T.LEN_RATE
FROM TMP T
WHERE (CASE
WHEN (SAVE_RATE = NEXT_SAVE AND LEN_RATE = NEXT_LEN)
OR (SAVE_RATE = PRE_SAVE AND LEN_RATE = PRE_LEN)
THEN
1
ELSE
0
END) = 1
GROUP BY T.SAVE_RATE, T.LEN_RATE
ORDER BY 1),
TMP3
AS (SELECT PB_DATE，SAVE_RATE,LEN_RATE
FROM TB T
WHERE NOT EXISTS
(SELECT NULL
FROM TMP2 R
WHERE R.SAVE_RATE = T.SAVE_RATE
AND R.LEN_RATE = T.LEN_RATE
AND R.PB_DATE = T.PB_DATE))
SELECT PB_DATE AS START_DATE,
LEAD (PB_DATE, 1, DATE ‘9999-12-31‘) OVER (ORDER BY PB_DATE) - 1
AS END_DATE,
SAVE_RATE,
LEN_RATE
FROM TMP3;

标签：ast with for group dual 复数 rac form table

Oracle根据连续性日期的重复数据取最大或最小值日期

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