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Oracle中使用Table()函数解决For循环中不写成 in (l_idlist)形式的问题

时间:2021-07-01 10:21:17 帮助过:4人阅读

 

解决方案:

 

1 CREATE OR REPLACE TYPE type_split IS TABLE OF VARCHAR2 (4000);
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 create or replace function split(p_list varchar2,p_sep varchar2 := ‘,‘) return type_split pipelined IS  l_idx pls_integer;  v_list varchar2(50) := p_list;  begin       loop            l_idx := instr(v_list,p_sep);            if l_idx > 0 then                pipe row(substr(v_list,1,l_idx-1));                v_list := substr(v_list,l_idx+length(p_sep));            else                 pipe row(v_list);                 exit;            end if;       end loop;       return;  end split;

此时修改getidlist代码如下:

 

 

1 2 3 4 5 6 7 8 9 10 11 12 create or replace procedure getidlist is   l_idlist varchar2(200); begin   l_idlist:=‘1,2,3,4‘;   for brrs in (select * from bldroom where bldroomid in (select column_value from table(split(l_idlist,‘,‘))))   loop       brrs.structure:=‘钢混‘;   end loop; end; / show err;

 

执行:exec getidlist;

提示错误:ORA-22905: cannot access rows from a non-nested table item

 

再次修改getidlist代码如下:

 

1 2 3 4 5 6 7 8 9 10 11 12 13 14 create or replace procedure getidlist is   brRow    bldroom%rowtype;   l_idlist varchar2(200); begin   l_idlist:=‘1,2,3,4‘;   for idrs in (select column_value from table(split(l_idlist,‘,‘)))   loop       select * into brRow from bldroom where bldroomid=idrs.column_value;       brRow.structure:=‘ssss‘;   end loop; end; / show err;

 

 

OK,搞定。

 

附:PL/SQL表---table()函数用法

摘录

 

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 /* 利用table()函数,我们可以将PL/SQL返回的结果集代替table。 oracle内存表在查询和报表的时候用的比较多,它的速度相对物理表要快几十倍。 */ /* simple example: 1、table()结合数组: */   create or replace type t_test as object( id integer, rq date, mc varchar2(60) );   create or replace type t_test_table as table of t_test;   create or replace function f_test_array(n in number default null) return t_test_table as v_test t_test_table := t_test_table(); begin for i in 1 .. nvl(n,100) loop v_test.extend(); v_test(v_test.count) := t_test(i,sysdate,‘mc‘||i); end loop; return v_test; end f_test_array; /   select * from table(f_test_array(10));   select * from the(select f_test_array(10) from dual);   /* 2、table()结合PIPELINED函数: */   create or replace function f_test_pipe(n in number default null) return t_test_table PIPELINED as v_test t_test_table := t_test_table(); begin for i in 1 .. nvl(n,100) loop pipe row(t_test(i,sysdate,‘mc‘||i)); end loop; return; end f_test_pipe; /   select * from table(f_test_pipe(20));   select * from the(select f_test_pipe(20) from dual);   /* 3、table()结合系统包: */   create table test (id varchar2(20)); insert into test values(‘1‘); commit; explain plan for select * from test; select * from table(dbms_xplan.display);

 

关于错误:ORA-22905: cannot access rows from a non-nested table item 的解决方案,不知各位大侠有没有更好的解决方案?请指教。

Oracle中使用Table()函数解决For循环中不写成 in (l_idlist)形式的问题

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