时间:2021-07-01 10:21:17 帮助过:18人阅读
1.表中有id和name 两个字段,查询出name重复的所有数据
1 |
select * from xi a where (a.username) in ( select username from xi group by username having count (*) > 1)
|
2、查询出所有数据进行分组之后,和重复数据的重复次数的查询数据,先列下:
1 |
select count (username) as ‘重复次数‘ ,username from xi group by username having count (*)>1 order by username desc
|
3、一下为 查看别人的 结果,现列下:查询及删除重复记录的方法大全
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
1 2 |
select * from people
where peopleId in ( select peopleId from people group by peopleId having count (peopleId) > 1)
|
2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
1 2 3 |
delete from people
where peopleId in ( select peopleId from people group by peopleId having count (peopleId) > 1)
and rowid not in ( select min (rowid) from people group by peopleId having count (peopleId )>1)
|
3、查找表中多余的重复记录(多个字段)
1 2 |
select * from vitae a
where (a.peopleId,a.seq) in ( select peopleId,seq from vitae group by peopleId,seq having count (*) > 1)
|
4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
1 2 3 |
delete from vitae a
where (a.peopleId,a.seq) in ( select peopleId,seq from vitae group by peopleId,seq having count (*) > 1)
and rowid not in ( select min (rowid) from vitae group by peopleId,seq having count (*)>1)
|
5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
1 2 3 |
select * from vitae a
where (a.peopleId,a.seq) in ( select peopleId,seq from vitae group by peopleId,seq having count (*) > 1)
and rowid not in ( select min (rowid) from vitae group by peopleId,seq having count (*)>1)
|
(二)
比方说
在A表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
1 |
Select Name , Count (*) From A Group By Name Having Count (*) > 1
|
如果还查性别也相同大则如下:
1 |
Select Name ,sex, Count (*) From A Group By Name ,sex Having Count (*) > 1
|
(三)
方法一
1 2 3 4 5 6 7 8 9 10 11 |
declare @ max integer ,@id integer
declare cur_rows cursor local for
select 主字段, count (*) from 表名 group by 主字段 having count (*) >;
open cur_rows fetch cur_rows into @id,@maxwhile @@fetch_status=0
begin
select @ max = @ max -1
set rowcount @ max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@maxend
close cur_rows
set rowcount 0
|
方法二"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复,比较容易解决,使用
1 |
select distinct * from tableName
|
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录(重复记录保留1条),
可以按以下方法删除
1 2 3 4 |
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
|
发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下 假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集
1 2 3 |
select identity( int ,1,1) as autoID, * into #Tmp from tableName
select min (autoID) as autoID into #Tmp2 from #Tmp group by Name ,autoID
select * from #Tmp where autoID in ( select autoID from #tmp2)
|
最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)
(四)查询重复
1 |
select * from tablename where id in ( select id from tablenamegroup by idhaving count (id) > 1)
|
对一个字段查找重复记录
根据sample_code字段找到重复记录
1 |
SELECT * FROM tb_table WHERE sample_code IN ( SELECT sample_code FROM tb_table GROUP BY sample_code HAVING COUNT (sample_code) > 1 );
|
对多个字段查找重复记录(这里以2个为例)
根据name和code字段找到重复记录
1 2 3 4 |
SELECT * from ( SELECT *, CONCAT( name ,code) as nameAndCode from tb_table) t WHERE t.nameAndCode in
(
SELECT nameAndCode from ( SELECT CONCAT( name ,code) as nameAndCode from tb_table) tt GROUP BY nameAndCode HAVING count (nameAndCode) > 1
)
|
MySQL根据某一个或者多个字段查找重复数据的sql语句
标签:aci 分组 tps count string 存在 操作方法 container cell