Oracle-left join两表关联只取B表匹配到的第一条记录

create table A(ANAME varchar(20));
insert into A values(‘alan‘);
insert into A values(‘Alee‘);
insert into A values(‘aspn‘);

 
create table B
(
BNo varchar(10),
BTell varchar(20),
Name varchar(20)
);
insert into B values(‘NO1‘,‘1366666‘,‘alan‘);
insert into B values(‘NO1‘,‘1388888‘,‘alan‘);
insert into B values(‘NO1‘,‘1399999‘,‘alan‘);
insert into B values(‘NO2‘,‘1333333‘,‘Alee‘);
insert into B values(‘NO3‘,‘1311111‘,‘aspn‘);
insert into B values(‘NO3‘,‘1322222‘,‘aspn‘);

直接关联查询的话，结果如下

需求是只要每个人的第一条记录（按BTELL排序）

select *
  from a
  left join (select *
               from (select b. *,
                            (row_number()
                             over(partition by bno order by BTell desc)) px
                       from b) e
              where px = 1) t
    on a.aname = t.name;

查询结果如下

参考：https://www.cnblogs.com/luxd/p/8527457.html

Oracle-left join两表关联只取B表匹配到的第一条记录

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