MySQL面试题

| emp_no | name   | age |

+--------+--------+-----+

|   1001 | 小明   |  18 |

|   1002 | 王强   |  20 |

|   1003 | 小雪   |  20 |

|   1004 | 小明   |  19 |

+--------+--------+-----+

select emp_no, name,age 
from emp 
where name in (
    select t.name from
     (    select name,count(name) as num 
         from emp 
         group by name 
         having num > 1
     )t
) 
order by age desc;

MySQL面试题

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