mysql之存储过程（四）--批量更新操作
时间：2021-07-01 10:21:17
帮助过：126人阅读
=b.busi_id and b.pid=1242343324),modified=now() where pid=21343
因此，写一个存储过程解决，存储过程一条条处理，太慢且消耗本地IO，所以写了个批量更新的存储过程。
如下：
DELIMITER &&
CREATE PROCEDURE updateTimeV1(IN comCount bigint)
BEGIN
#Routine body goes here...
declare i int;
set i=0;
set @sum=(SELECT count(DISTINCT order_no) FROM `B` WHERE `pid`=1242343324 and status=9 );
set @log = "log query ....";
select CONCAT(@log,@sum," 条");
while i<=@sum do
set i=i+1;
set @busi_id =( SELECT DISTINCT busi_id FROM `A` WHERE `pid`=1242343324 limit i,1);
set @other_col =(SELECT other_col FROM `B` where `pid`=1242343324 and yn =1 and `busi_id` = @busi_id limit 1);
if @busi_id is NULL THEN
select CONCAT(@log," busi_id is null");
elseif @other_col is NULL THEN
select CONCAT(@log," other_col is null");
else
#START TRANSACTION;
/** 关闭事务的自动提交 */
SET autocommit = 0;
update A set new_column =@other_col,modified = now() where `pid`=1242343324 and busi_id=@busi_id and status =15;
## if mod(i,comCount)=0 then commit;
if mod(i,1000)=0 then commit;
end if;
end if;
end while;
commit; #最后不足1000条时提交
SET autocommit = 1;
END&&
delimiter ;
备注：
1、测试了一下一条一条执行，一小时大概20W行更新
2、mod(i,1000)这块得注意 ，如果把set i=i+1;放到最后，在上面的存储过程批量就不会生效。mysql之存储过程（四）--批量更新操作
标签：color 关联 proc family upd 生产环境 操作 ica datetime
