当前位置:Gxlcms > 数据库问题 > SQL答案

SQL答案

时间:2021-07-01 10:21:17 帮助过:8人阅读

table student( sno varchar2(10) primary key, sname varchar2(20), sage number(2), ssex varchar2(5) ); create table teacher( tno varchar2(10) primary key, tname varchar2(20) ); create table course( cno varchar2(10), cname varchar2(20), tno varchar2(20), constraint pk_course primary key (cno,tno) ); create table sc( sno varchar2(10), cno varchar2(10), score number(4,2), constraint pk_sc primary key (sno,cno) ); /*******初始化学生表的数据******/ insert into student values (s001,张三,23,); insert into student values (s002,李四,23,); insert into student values (s003,吴鹏,25,); insert into student values (s004,琴沁,20,); insert into student values (s005,王丽,20,); insert into student values (s006,李波,21,); insert into student values (s007,刘玉,21,); insert into student values (s008,萧蓉,21,); insert into student values (s009,陈萧晓,23,); insert into student values (s010,陈美,22,); commit; /******************初始化教师表***********************/ insert into teacher values (t001, 刘阳); insert into teacher values (t002, 谌燕); insert into teacher values (t003, 胡明星); commit; /***************初始化课程表****************************/ insert into course values (c001,J2SE,t002); insert into course values (c002,Java Web,t002); insert into course values (c003,SSH,t001); insert into course values (c004,Oracle,t001); insert into course values (c005,SQL SERVER 2005,t003); insert into course values (c006,C#,t003); insert into course values (c007,JavaScript,t002); insert into course values (c008,DIV+CSS,t001); insert into course values (c009,PHP,t003); insert into course values (c010,EJB3.0,t002); commit; /***************初始化成绩表***********************/ insert into sc values (s001,c001,78.9); insert into sc values (s002,c001,80.9); insert into sc values (s003,c001,81.9); insert into sc values (s004,c001,60.9); insert into sc values (s001,c002,82.9); insert into sc values (s002,c002,72.9); insert into sc values (s003,c002,81.9); insert into sc values (s001,c003,59); commit; select * from teacher; select * from student; select * from course; select * from sc; --1、查询“c001”课程比“c002”课程成绩高的所有学生的学号; SELECT A.SNO FROM (SELECT SNO, SCORE FROM SC WHERE CNO = c001) A INNER JOIN (SELECT SNO, SCORE FROM SC WHERE CNO = c002) B ON A.SNO = B.SNO WHERE A.SCORE > B.SCORE; --2、查询平均成绩大于60 分的同学的学号和平均成绩; SELECT SNO, AVG(SCORE) FROM SC GROUP BY SNO HAVING AVG(SCORE) > 60; --3、查询所有同学的学号、姓名、选课数、总成绩; SELECT S.SNO, S.SNAME, COUNT(CNO), SUM(SCORE) FROM STUDENT S INNER JOIN SC ON S.SNO = SC.SNO GROUP BY S.SNO, S.SNAME; --4、查询姓“刘”的老师的个数; SELECT COUNT(TNAME) FROM TEACHER WHERE TNAME LIKE 刘%; --5、查询没学过“谌燕”老师课的同学的学号、姓名; SELECT SNO, SNAME FROM STUDENT WHERE SNO NOT IN (SELECT DISTINCT SNO FROM SC INNER JOIN COURSE C ON SC.CNO = C.CNO INNER JOIN TEACHER T ON C.TNO = T.TNO WHERE TNAME = 谌燕); SELECT SNO, SNAME FROM STUDENT SS WHERE NOT EXISTS (SELECT 1 FROM (SELECT DISTINCT SNO FROM SC INNER JOIN COURSE C ON SC.CNO = C.CNO INNER JOIN TEACHER T ON C.TNO = T.TNO WHERE TNAME = 谌燕) TT WHERE SS.SNO = TT.SNO); SELECT SNO, SNAME FROM STUDENT SS WHERE NOT EXISTS (SELECT DISTINCT SNO FROM SC INNER JOIN COURSE C ON SC.CNO = C.CNO INNER JOIN TEACHER T ON C.TNO = T.TNO WHERE TNAME = 谌燕 AND SS.SNO = SC.SNO); --6、查询学过“c001”并且也学过编号“c002”课程的同学的学号、姓名; SELECT S.SNO, S.SNAME FROM STUDENT S INNER JOIN SC S1 ON S.SNO = S1.SNO WHERE CNO = c001 AND EXISTS (SELECT * FROM SC S2 WHERE S1.SNO = S2.SNO AND S2.CNO = c002); SELECT S.SNO, S.SNAME FROM STUDENT S INNER JOIN SC S1 ON S.SNO = S1.SNO WHERE CNO = c001 AND S1.SNO IN (SELECT S2.SNO FROM SC S2 WHERE S2.CNO = c002); SELECT S.SNO, S.SNAME FROM STUDENT S INNER JOIN SC S1 ON S.SNO = S1.SNO WHERE CNO = c001 AND EXISTS (SELECT 1 FROM SC S2 WHERE S1.SNO = S2.SNO AND S2.CNO = c002); --7、查询学过“谌燕”老师所教的所有课的同学的学号、姓名; SELECT DISTINCT S.SNO, S.SNAME FROM STUDENT S INNER JOIN SC ON S.SNO = SC.SNO INNER JOIN COURSE C ON SC.CNO = C.CNO INNER JOIN TEACHER T ON C.TNO = T.TNO WHERE T.TNAME = 谌燕 ORDER BY SNO; SELECT S.SNO, S.SNAME FROM STUDENT S WHERE EXISTS (SELECT SNO FROM SC INNER JOIN COURSE C ON SC.CNO = C.CNO INNER JOIN TEACHER T ON C.TNO = T.TNO WHERE T.TNAME = 谌燕 AND S.SNO = SC.SNO); SELECT S.SNO, S.SNAME FROM STUDENT S WHERE SNO IN (SELECT SNO FROM SC INNER JOIN COURSE C ON SC.CNO = C.CNO INNER JOIN TEACHER T ON C.TNO = T.TNO WHERE T.TNAME = 谌燕); --8、查询课程编号“c002”的成绩比课程编号“c001”课程低的所有同学的学号、姓名; SELECT S1.SNO FROM SC S1 WHERE S1.CNO = c001 AND EXISTS (SELECT * FROM SC S2 WHERE S1.SNO = S2.SNO AND S2.CNO = c002 AND S1.SCORE > S2.SCORE); SELECT S.SNO, S.SNAME FROM STUDENT S INNER JOIN SC S1 ON S.SNO = S1.SNO AND S1.CNO = c001 AND EXISTS (SELECT * FROM SC S2 WHERE S1.SNO = S2.SNO AND S2.CNO = c002 AND S1.SCORE > S2.SCORE); --------------------------------------- SELECT S.SNO, S.SNAME FROM STUDENT S INNER JOIN (SELECT SNO, SCORE FROM SC WHERE CNO = c001) A ON S.SNO = A.SNO INNER JOIN (SELECT SNO, SCORE FROM SC WHERE CNO = c002) B ON A.SNO = B.SNO WHERE A.SCORE > B.SCORE; --9、查询所有课程成绩小于60 分的同学的学号、姓名; SELECT S.SNO, S.SNAME FROM STUDENT S WHERE SNO NOT IN (SELECT SNO FROM SC WHERE SCORE > 60); SELECT S.SNO, S.SNAME FROM STUDENT S WHERE NOT EXISTS (SELECT SNO FROM SC WHERE SCORE > 60 AND SC.SNO = S.SNO); --10、查询没有学全所有课的同学的学号、姓名; --11、查询至少有一门课与学号为“s001”的同学所学相同的同学的学号和姓名; --12、查询至少学过学号为“s001”同学所有一门课的其他同学学号和姓名; --13、把“SC”表中“谌燕”老师教的课的成绩都更改为此课程的平均成绩; --14、查询和“s001”号的同学学习的课程完全相同的其他同学学号和姓名; --15、删除学习“谌燕”老师课的SC 表记录; --16、向SC 表中插入一些记录,这些记录要求符合以下条件:没有上过编号“c002”课程的同学学号、“c002”号课的平均成绩; --17、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分 --18、按各科平均成绩从低到高和及格率的百分数从高到低顺序 --19、查询不同老师所教不同课程平均分从高到低显示 --21、查询各科成绩前三名的记录:(不考虑成绩并列情况) --22、查询每门课程被选修的学生数 --23、查询出只选修了一门课程的全部学生的学号和姓名 --24、查询男生、女生人数 --25、查询姓“张”的学生名单 --26、查询同名同性学生名单,并统计同名人数 --27、1981 年出生的学生名单(注:Student 表中Sage 列的类型是number) --28、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 --29、查询平均成绩大于85 的所有学生的学号、姓名和平均成绩 --30、查询课程名称为“数据库”,且分数低于60 的学生姓名和分数 ---------------------------------------------------------------------------------------------------------------- --31、查询所有学生的选课情况; --32、查询任何一门课程成绩在70 分以上的姓名、课程名称和分数; --33、查询不及格的课程,并按课程号从大到小排列 --34、查询课程编号为c001 且课程成绩在80 分以上的学生的学号和姓名; --35、求选了课程的学生人数 --36、查询选修“谌燕”老师所授课程的学生中,成绩最高的学生姓名及其成绩 --37、查询各个课程及相应的选修人数 --38、查询不同课程成绩相同的学生的学号、课程号、学生成绩 --39、查询每门功课成绩最好的前两名 --40、统计每门课程的学生选修人数(超过10 人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列 --41、检索至少选修两门课程的学生学号 --42、查询全部学生都选修的课程的课程号和课程名 --43、查询没学过“谌燕”老师讲授的任一门课程的学生姓名 --44、查询两门以上不及格课程的同学的学号及其平均成绩 --45、检索“c004”课程分数小于60,按分数降序排列的同学学号 --46、删除“s002”同学的“c001”课程的成绩 -- -- --

 

SQL答案

标签:asc   css   like   总成绩   并且   web   order   条件   显示   

人气教程排行