时间:2021-07-01 10:21:17 帮助过:28人阅读
废话不多说了,直接给大家贴实现此功能的正则表达式代码了,具体代码如下所示:
#import <Foundation/Foundation.h> int main() { // ? == {0,1} // * == {0,无穷} // + == {1,无穷} // \d == [0-9] // \w == [A-Za-z_0-9] // * 的意思是可有可无 // [a|b|c]+ 表示三个至少出现一次或多次 //检测电话号码是否正确 NSString *tel = @""; //正则表达式 NSString *regex = @"^\\d*$"; // NSString *regex = @"^[0-9]{3,4}-[0-9]{7,8}$"; NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF MATCHES%@",regex];//创建需要满足上面的正则表达式的谓词 NSLog(@"该电话号码:%d",[predicate evaluateWithObject:tel]); //用户名 (第一位必须是字母,6-16位,只能有字母,数字或下划线) NSString *user = @"m54355"; NSString *regex1 = @"^[A-Za-z]\\w{5,15}$"; NSPredicate *predicate1 = [NSPredicate predicateWithFormat:@"SELF MATCHES%@",regex1]; // NSLog(@"该电话号码:%d",[predicate1 evaluateWithObject:user]); // //身份证 // NSString *user1 = @"610125199301300814"; // NSString *regex2 = @"^\\d{17}[\\dxX]$"; // NSPredicate *predicate2 = [NSPredicate predicateWithFormat:@"SELF MATCHES%@",regex2]; // NSLog(@"该身份证:%d",[predicate2 evaluateWithObject:user1]); //邮箱 NSString *mailbox = @"101707383@qq.com"; NSString *regex3 = @"^[a-zA-Z0-9._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}$"; NSPredicate *predicate3 = [NSPredicate predicateWithFormat:@"SELF MATCHES%@",regex3]; // NSLog(@"该邮箱:%d",[predicate3 evaluateWithObject:mailbox]); //手机号 // NSString *phone = @"18709259205"; // NSString *regex4 = @"^1[3|4|5|7|8]\\d{9}$"; // NSPredicate *predicate4 = [NSPredicate predicateWithFormat:@"SELF MATCHES%@",regex4]; // NSLog(@"该手机:%d",[predicate4 evaluateWithObject:phone]); if ([predicate1 evaluateWithObject:user] == 1) { if ([predicate3 evaluateWithObject:mailbox] == 1) { NSLog(@"登录成功"); } }else{ NSLog(@"错误"); } return 0; }