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pythonpycurl验证basic和digest认证的方法

时间:2021-07-01 10:21:17 帮助过:20人阅读

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简介

pycurl类似于Python的urllib,但是pycurl是对libcurl的封装,速度更快。

本文使用的是pycurl 7.43.0.1版本。

Apache下配置Basic认证

生成basic密码文件

  1. htpasswd -bc passwd.basic test 123456

开启mod_auth_basic

  1. LoadModule auth_basic_module modules/mod_auth_basic.so

配置到具体目录

  1. <Directory "D:/test/basic">
  2. AuthName "Basic Auth Dir"
  3. AuthType Basic
  4. AuthUserFile conf/passwd.basic
  5. require valid-user
  6. </Directory>

重启Apache

Apache下配置Digest认证

生成Digest密码文件

  1. htdigest -c passwd.digest "Digest Encrypt" test

开启mod_auth_digest

  1. LoadModule auth_digest_module modules/mod_auth_digest.so

配置到具体目录

  1. <Directory "D:/test/digest">
  2. AuthType Digest
  3. AuthName "Digest Encrypt" # 要与密码的域一致
  4. AuthDigestProvider file
  5. AuthUserFile conf/passwd.digest
  6. require valid-user
  7. </Directory>

重启Apache

验证Basic认证

  1. # -*- coding: utf-8 -*-
  2. import pycurl
  3. try:
  4. from io import BytesIO
  5. except ImportError:
  6. from StringIO import StringIO as BytesIO
  7. buffer = BytesIO()
  8. c = pycurl.Curl()
  9. c.setopt(c.URL, 'http://test/basic/')
  10. c.setopt(c.WRITEDATA, buffer)
  11. c.setopt(c.HTTPAUTH, c.HTTPAUTH_BASIC)
  12. c.setopt(c.USERNAME, 'test')
  13. c.setopt(c.PASSWORD, '123456')
  14. c.perform()
  15. print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
  16. print(buffer.getvalue())
  17. c.close()

验证Digest认证

  1. # -*- coding: utf-8 -*-
  2. import pycurl
  3. try:
  4. from io import BytesIO
  5. except ImportError:
  6. from StringIO import StringIO as BytesIO
  7. buffer = BytesIO()
  8. c = pycurl.Curl()
  9. c.setopt(c.URL, 'http://test/digest/')
  10. c.setopt(c.WRITEDATA, buffer)
  11. c.setopt(c.HTTPAUTH, c.HTTPAUTH_DIGEST)
  12. c.setopt(c.USERNAME, 'test')
  13. c.setopt(c.PASSWORD, '123456')
  14. c.perform()
  15. print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
  16. print(buffer.getvalue())
  17. c.close()


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