时间:2021-07-01 10:21:17 帮助过:72人阅读
enumerate(thing)
, whereis either an iterator or a sequence, returns a iterator that will return (0,[0])
, (1,[1])
, (2,[2])
, and so forth.A common idiom to change every element of a list looks like this:
用法:在同时需要index 和 value 值得时候可以使用
line = [1,3,'dfd','jdjfjd'] for i in range(len(line)): item = line[i] print(i,"--->",item) #运行结果: ---> 1 ---> 3 ---> dfd ---> jdjfjd
等价于下列代码:
line = [1,3,'dfd','jdjfjd'] for i,item in enumerate(line): print(i,"-------",item)
line 是个 string 包含 0 和 1,要把1都找出来:
#方法一
def read_line(line):
sample = {}
n = len(line)
for i in range(n):
if line[i]!='0':
sample[i] = int(line[i])
return sample
#方法二
def xread_line(line):
return((idx,int(val)) for idx, val in enumerate(line) if val != '0')
print read_line('0001110101')
print list(xread_line('0001110101'))
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