时间:2021-07-01 10:21:17 帮助过:457人阅读
加入我们需要处理一串个位数(0~9),奇数时需要循环打印它;偶数则等待对应时长并完成所有任务;0则是错误,但不需要终止任务,可以自定义一些处理。
定义func函数处理需求
callback处理返回结果,只有偶数和0返回;奇数会一直执行;要控制线程池状态,则需要针对偶数和0时抛出异常,并捕获异常处理。
threadpool定义线程池并发
# -*- coding: utf-8 -*- from threadpool import makeRequests, ThreadPool import time from multiprocessing import Process
class Finish(SyntaxWarning): pass
class PauseInfo(SyntaxWarning): pass pause_num = 0
0时返回False,其他偶数返回True
def func(para): if para == pause_num: print('start for %d and wait %ds' % (para, 4)) time.sleep(4) print('error bcs ',para) return False if para % 2 == 0: print('start for %d and wait %ds' % (para, para)) time.sleep(para) print('stop for', para) return True while True: print('continue for', para) time.sleep(para)
def callback(request, result): if result: raise Finish else: raise PauseInfo
Finish标识任务完成,再次诱发异常退出线程池处理;
def main_thread(paras): pool = ThreadPool(10) requests = makeRequests(callable_=func, args_list=paras, callback=callback) [pool.putRequest(req) for req in requests] while True: try: pool.wait() except Finish as e: raise SystemExit except PauseInfo as e: print('Pause bcs %d but will continue' % pause_num) except Exception as e: print('Unknown error so will quit') raise SystemExit
if name == 'main': while True: s = input('Input number list to test and any other word to quit\n') paras = [] for para in s: if para.isnumeric(): paras.append(int(para)) else: break try: thread_test = Process(target=main_thread, args=(paras,)) thread_test.start() thread_test.join(timeout=20) except TimeoutError as e: print('task timeout') except Exception as e: print('unknow error:',e)
处理108,看打印可以看到,1被循环处理,0处理的时候报错;8处理完毕则任务结束
Input number list to test and any other word to quit
108
continue for 1
start for 0 and wait 4s
start for 8 and wait 8s
continue for 1
continue for 1
continue for 1
error bcs 0
continue for 1
Pause bcs 0 but will continue
continue for 1
continue for 1
continue for 1
continue for 1
stop for 8
Input number list to test and any other word to quit
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