python列表list去重

一.{}.fromkeys(list).keys()

list2 = {}.fromkeys(list1).keys()

二.set

list2 = list(set(list1))

三.itertools.grouby

ids = [1,4,3,3,4,2,3,4,5,6,1]

ids.sort()

it = itertools.groupby(ids)

for k, g in it:

print k

四,笨方法

ids = [1,2,3,3,4,2,3,4,5,6,1]

news_ids = []

for id in ids:

if id not in news_ids:

news_ids.append(id)

print news_ids

这四种都有个特点，去重后元素排序变了，效率 据说第一种比第二种快一点

五.索引再次排序 这种可以去重并且保持元素顺序

#要结果是[1, 4, 3, 2, 5, 6] 不要[1, 2, 3, 4, 5, 6]

ids = [1,4,3,3,4,2,3,4,5,6,1]

news_ids = list(set(ids))

news_ids.sort(key=ids.index)

print news_ids #[1, 4, 3, 2, 5, 6]

六：Reduce

ids = [1,4,3,3,4,2,3,4,5,6,1]

func = lambda x,y:x if y in x else x + [y]

print reduce(func, [[], ] + ids)#[1, 4, 3, 2, 5, 6]