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python三级菜单

时间:2021-07-01 10:21:17 帮助过:36人阅读

  1. menu = {
  2. '北京':{
  3. '海淀':{
  4. '五道口':{
  5. 'soho':{},
  6. '网易':{},
  7. 'google':{}
  8. },
  9. '中关村':{
  10. '爱奇艺':{},
  11. '汽车之家':{},
  12. 'youku':{},
  13. },
  14. '上地':{
  15. '百度':{},
  16. },
  17. },
  18. '昌平':{
  19. '沙河':{
  20. '老男孩':{},
  21. '北航':{},
  22. },
  23. '天通苑':{},
  24. '回龙观':{},
  25. },
  26. '朝阳':{},
  27. '东城':{},
  28. },
  29. '上海':{
  30. '闵行':{
  31. "人民广场":{
  32. '炸鸡店':{}
  33. }
  34. },
  35. '闸北':{
  36. '火车战':{
  37. '携程':{}
  38. }
  39. },
  40. '浦东':{},
  41. },
  42. '山东':{},
  43. }

二逼青年版:

  1. while True:
  2. for key in menu:
  3. print(key)
  4. choice = input(">>>:")
  5. if len(choice) == 0: continue
  6. if choice not in menu:continue
  7. while True:
  8. for key2 in menu[choice]:
  9. print(key2)
  10. choice2 = input(">>>:")
  11. if len(choice2) == 0: continue
  12. if choice2 == "b": break
  13. if choice2 not in menu[choice]: continue
  14. while True:
  15. for key3 in menu[choice][choice2]:
  16. print(key3)
  17. choice3 = input(">>>:")
  18. if len(choice3) == 0: continue
  19. if choice3 == "b": break
  20. if choice3 not in menu[choice][choice2]: continue
  21. while True:
  22. for key4 in menu[choice][choice2][choice3]:
  23. print(key4)
  24. choice4 = input(">>>:")
  25. if len(choice4) == 0: continue
  26. if choice4 == "b": break
  27. if choice4 not in menu[choice][choice2][choice3]: continue

文艺青年版:

  1. current_level = menu
  2. last_level = []
  3. while True:
  4. for key in current_level:
  5. print(key)
  6. choice = input(">>>:")
  7. if len(choice) == 0:continue
  8. if choice == "b":
  9. if not last_level : break
  10. current_level = last_level[-1]
  11. last_level.pop()
  12. if choice not in current_level:continue
  13. last_level.append(current_level)
  14. current_level = current_level[choice]

作者:terry
blog:http://www.cnblogs.com/kkterry/
Weibo:http://weibo.com/kkterry
E-mail:doubleginger@163.com
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