时间:2021-07-01 10:21:17 帮助过:66人阅读
问题描述:对给定页码n,计算出全部页码中分别用到多少次数字0,1,2,3,4...,9
实例代码如下:
def count_num1(page_num): num_zero = 0 num_one = 0 num_two = 0 num_three = 0 num_four = 0 num_five = 0 num_six = 0 num_seven = 0 num_eight = 0 num_nine = 0 page_list = range(1,page_num + 1) for page in page_list: page = str(page) num_zero += page.count('0') num_one += page.count('1') num_two += page.count('2') num_three += page.count('3') num_four += page.count('4') num_five += page.count('5') num_six += page.count('6') num_seven += page.count('7') num_eight += page.count('8') num_nine += page.count('9') result = [num_zero,num_one,num_two,num_three,num_four,num_five,num_six,num_seven,num_eight,num_nine] return result print count_num1(13)
上面这段代码略显臃肿,所以改了下代码。
改后的代码如下:
def count_num2(page_num): page_list = range(1,page_num + 1) result = [0 for i in range(10)] for page in page_list: page = str(page) for i in range(10): temp = page.count(str(i)) result[i] += temp return result print count_num2(13)
本文实例测试运行环境为Python2.7.6
程序输出结果为:
[1, 6, 2, 2, 1, 1, 1, 1, 1, 1]
希望本文所述对大家的Python程序设计有所帮助。