时间：2021-07-01 10:21:17 帮助过：28人阅读
修改前：[脚本之家]Mac OS X for Unix Geeks[www.gxlcms.com].mobi
修改后：Mac OS X for Unix Geeks.mobi
python代码如下:
def rename_dir(dir,regex,f):
if not os.path.isdir(dir) or not os.path.exists(dir) :
print("The input is not one directory or not exist.")
for root,subdirs,files in os.walk(dir):
for name in files:
oldname = name
newname = re.sub(regex,f,name)
print("Before : " + os.path.join(root,oldname))
print("After : " + os.path.join(root,newname))
if not name == newname and not os.path.exists(os.path.join(root,newname)):
os.rename(os.path.join(root,oldname),os.path.join(root,newname))
for dir in subdirs:
rename_dir(os.path.join(root,dir))
rename_dir("C:\\Python31\\test","\[.*\](.*)\[www.gxlcms.com\](.*)",lambda m:m.group(1)+m.group(2))
用perl写了下，感觉代码也没有少写多少
my $regex = "\\[.*\\](.*)\\[www.gxlcms.com\\](.*)";
# $replace doesn't work
my $replace = "\$1\$2";
sub wanted {
my $name = $File::Find::name;
if( -f $name){
my $newname =$name;
$newname =~ s/$regex/$1$2/;
print "Before: $File::Find::name\n";
print "After : $newname\n";
if( !-e $newname) {
rename($name, $newname);
}
}
}
sub rename_dir{
my ($dir,) = @_;
if (!-d $dir || !-e $dir){
print"The input is not directory or not exist.";
}
find(\&wanted, $dir);
}
&rename_dir("c:\\perl\\test");
perl 实现2
my $regex = "\\[.*\\](.*)\\[www.gxlcms.com\\](.*)";
# $replace doesn't work
my $replace = "\$1\$2";
sub rename_dir{
my $dir = shift;
if (!-d $dir || !-e $dir){
print"The input is not directory or not exist.";
}
opendir(DIR, $dir) || die "Cannot opendir $dir.";
foreach (readdir(DIR)) {
if ($_ eq '.' || $_ eq '..') {next;}
my $name = $dir.'/'.$_;
if(-d $name){
rename_dir($name);
next;
}
my $newname =$_;
$newname =~ s/$regex/$1$2/;
$newname = $dir.'/'.$newname;
print "Before : $name\n";
print "After : $newname\n";
rename($name,$newname);
}
#closedir(DIR);
}
&rename_dir("c:\\perl\\test");