当前位置:Gxlcms > Python > python列表操作实例

python列表操作实例

时间:2021-07-01 10:21:17 帮助过:20人阅读

本文实例讲述了python列表操作的方法。分享给大家供大家参考。

具体实现方法如下:

代码如下:

class Node:
"""Single node in a data structure"""

def __init__(self, data):
"""Node constructor"""

self._data = data
self._nextNode = None

def __str__(self):
"""Node data representation"""

return str(self._data)

class List:
"""Linked list"""

def __init__(self):
"""List constructor"""

self._firstNode = None
self._lastNode = None

def __str__(self):
"""List string representation"""

if self.isEmpty():
return "empty"

currentNode = self._firstNode
output = []

while currentNode is not None:
output.append(str(currentNode._data))
currentNode = currentNode._nextNode

return " ".join(output)

def insertAtFront(self, value):
"""Insert node at front of list"""

newNode = Node(value)

if self.isEmpty(): # List is empty
self._firstNode = self._lastNode = newNode
else: # List is not empty
newNode._nextNode = self._firstNode
self._firstNode = newNode

def insertAtBack(self, value):
"""Insert node at back of list"""

newNode = Node(value)

if self.isEmpty(): # List is empty
self._firstNode = self._lastNode = newNode
else: # List is not empty
self._lastNode._nextNode = newNode
self._lastNode = newNode

def removeFromFront(self):
"""Delete node from front of list"""

if self.isEmpty(): # raise exception on empty list
raise IndexError, "remove from empty list"

tempNode = self._firstNode

if self._firstNode is self._lastNode: # one node in list
self._firstNode = self._lastNode = None
else:
self._firstNode = self._firstNode._nextNode

return tempNode

def removeFromBack(self):
"""Delete node from back of list"""

if self.isEmpty(): # raise exception on empty list
raise IndexError, "remove from empty list"

tempNode = self._lastNode

if self._firstNode is self._lastNode: # one node in list
self._firstNode = self._lastNode = None
else:
currentNode = self._firstNode

# locate second-to-last node
while currentNode._nextNode is not self._lastNode:
currentNode = currentNode._nextNode

currentNode._nextNode = None
self._lastNode = currentNode

return tempNode

def isEmpty(self):
"""Returns true if List is empty"""

return self._firstNode is None

希望本文所述对大家的Python程序设计有所帮助。

人气教程排行