时间:2021-07-01 10:21:17 帮助过:52人阅读
import math import decimal def convert_to_code(num): """ 将数字转换为代码 """ def get_num(num, out=''): num = decimal.Decimal(num) codes = "abcdefghjkmnpqrstuvwxyz23456789ABCDEFGHJKMNPQRSTUVWXYZ" if num > 53: key = num % 54 num = math.floor(num / 54) - 1 return get_num(num, codes[int(key)] + out) else: return codes[int(num)] + out return get_num(num) def convert_to_num(code): """ 将代码转为数字 """ import math codes = "abcdefghjkmnpqrstuvwxyz23456789ABCDEFGHJKMNPQRSTUVWXYZ" num = 0 num = decimal.Decimal(num) i = len(code) for char in code: i -= 1 pos = codes.find(char) num += (54 ** i) * (pos + 1) num -= 1 # 任意数的 0 次方等于1,所以需要减去 return int(num)
希望本文所述对大家的Python程序设计有所帮助。