时间:2021-07-01 10:21:17 帮助过:531人阅读
#-*-coding:utf-8-*- #========================================== # 导入smtplib和MIMEText #========================================== from email.mime.text import MIMEText import smtplib #========================================== # 要发给谁,这里发给2个人 #========================================== mailto_list=["naughty610@qq.com","1034791200@qq.com"] #========================================== # 设置服务器,用户名、口令以及邮箱的后缀 #========================================== mail_host="smtp.qq.com" mail_user="naughty610" mail_pass="here is your password" mail_postfix="qq.com" #========================================== # 发送邮件 #========================================== def send_mail(to_list,sub,content): ''''' to_list:发给谁 sub:主题 content:内容 send_mail("aaa@126.com","sub","content") ''' me=mail_user+"<"+mail_user+"@"+mail_postfix+">" msg = MIMEText(content) msg['Subject'] = sub msg['From'] = me msg['To'] = ";".join(to_list) try: s = smtplib.SMTP() s.connect(mail_host) s.login(mail_user,mail_pass) s.sendmail(me, to_list, msg.as_string()) s.close() return True except Exception, e: print str(e) return False if __name__ == '__main__': if send_mail(mailto_list,"here is subject","here is content"): print "发送成功" else: print "发送失败"
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