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python实现将英文单词表示的数字转换成阿拉伯数字的方法

时间:2021-07-01 10:21:17 帮助过:276人阅读

本文实例讲述了python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下:

  1. import re
  2. _known = {
  3. 'zero': 0,
  4. 'one': 1,
  5. 'two': 2,
  6. 'three': 3,
  7. 'four': 4,
  8. 'five': 5,
  9. 'six': 6,
  10. 'seven': 7,
  11. 'eight': 8,
  12. 'nine': 9,
  13. 'ten': 10,
  14. 'eleven': 11,
  15. 'twelve': 12,
  16. 'thirteen': 13,
  17. 'fourteen': 14,
  18. 'fifteen': 15,
  19. 'sixteen': 16,
  20. 'seventeen': 17,
  21. 'eighteen': 18,
  22. 'nineteen': 19,
  23. 'twenty': 20,
  24. 'thirty': 30,
  25. 'forty': 40,
  26. 'fifty': 50,
  27. 'sixty': 60,
  28. 'seventy': 70,
  29. 'eighty': 80,
  30. 'ninety': 90
  31. }
  32. def spoken_word_to_number(n):
  33. """Assume n is a positive integer".
  34. assert _positive_integer_number('nine hundred') == 900
  35. assert spoken_word_to_number('one hundred') == 100
  36. assert spoken_word_to_number('eleven') == 11
  37. assert spoken_word_to_number('twenty two') == 22
  38. assert spoken_word_to_number('thirty-two') == 32
  39. assert spoken_word_to_number('forty two') == 42
  40. assert spoken_word_to_number('two hundred thirty two') == 232
  41. assert spoken_word_to_number('two thirty two') == 232
  42. assert spoken_word_to_number('nineteen hundred eighty nine') == 1989
  43. assert spoken_word_to_number('nineteen eighty nine') == 1989
  44. assert spoken_word_to_number('one thousand nine hundred and eighty nine') == 1989
  45. assert spoken_word_to_number('nine eighty') == 980
  46. assert spoken_word_to_number('nine two') == 92 # wont be able to convert this one
  47. assert spoken_word_to_number('nine thousand nine hundred') == 9900
  48. assert spoken_word_to_number('one thousand nine hundred one') == 1901
  49. """
  50. n = n.lower().strip()
  51. if n in _known:
  52. return _known[n]
  53. else:
  54. inputWordArr = re.split('[ -]', n)
  55. assert len(inputWordArr) > 1 #all single words are known
  56. #Check the pathological case where hundred is at the end or thousand is at end
  57. if inputWordArr[-1] == 'hundred':
  58. inputWordArr.append('zero')
  59. inputWordArr.append('zero')
  60. if inputWordArr[-1] == 'thousand':
  61. inputWordArr.append('zero')
  62. inputWordArr.append('zero')
  63. inputWordArr.append('zero')
  64. if inputWordArr[0] == 'hundred':
  65. inputWordArr.insert(0, 'one')
  66. if inputWordArr[0] == 'thousand':
  67. inputWordArr.insert(0, 'one')
  68. inputWordArr = [word for word in inputWordArr if word not in ['and', 'minus', 'negative']]
  69. currentPosition = 'unit'
  70. prevPosition = None
  71. output = 0
  72. for word in reversed(inputWordArr):
  73. if currentPosition == 'unit':
  74. number = _known[word]
  75. output += number
  76. if number > 9:
  77. currentPosition = 'hundred'
  78. else:
  79. currentPosition = 'ten'
  80. elif currentPosition == 'ten':
  81. if word != 'hundred':
  82. number = _known[word]
  83. if number < 10:
  84. output += number*10
  85. else:
  86. output += number
  87. #else: nothing special
  88. currentPosition = 'hundred'
  89. elif currentPosition == 'hundred':
  90. if word not in [ 'hundred', 'thousand']:
  91. number = _known[word]
  92. output += number*100
  93. currentPosition = 'thousand'
  94. elif word == 'thousand':
  95. currentPosition = 'thousand'
  96. else:
  97. currentPosition = 'hundred'
  98. elif currentPosition == 'thousand':
  99. assert word != 'hundred'
  100. if word != 'thousand':
  101. number = _known[word]
  102. output += number*1000
  103. else:
  104. assert "Can't be here" == None
  105. return(output)

希望本文所述对大家的Python程序设计有所帮助。

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