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php源码 fsockopen获取网页内容实例详解

时间:2021-07-01 10:21:17 帮助过:8人阅读

PHP fsockopen函数说明:

Open Internet or Unix domain socket connection(打开套接字链接)

Initiates a socket connection to the resource specified by target .

fsockopen() returns a file pointer which may be used together with the other file functions (such as fgets() , fgetss() , fwrite() , fclose() , and feof() ).就是返回一个文件句柄

开启PHP fsockopen这个函数

PHP fsockopen需要 PHP.ini 中 allow_url_fopen 选项开启。

使用fsockopen获取网页内容

具体源代码如下:

<?php
$host = "www.manongjc.com";
$page = "/index.htm";
$fp = fsockopen( "$host", 80, $errno, $errdesc );
if ( ! $fp ) {
 die ( "Couldn't connect to $host:\nError: $errno\nDesc: $errdesc\n" );
}

$request = "GET $page HTTP/1.0\r\n";
$request .= "Host: $host\r\n";
$request .= "Referer: http://www.manongjc.com/page.html\r\n";
$request .= "User-Agent: PHP test client\r\n\r\n";

$page = array();
fputs ( $fp, $request );
while ( ! feof( $fp ) ) {
 $page[] = fgets( $fp, 1024 );
}
fclose( $fp );
print "the server returned ".(count($page))." lines!";
?>





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