时间:2021-07-01 10:21:17 帮助过:188人阅读
sql code
--ascii字符
select n,x=cast(n as binary(2)),u=nchar(n) from nums where n between 32 and 126
--unicode中文字符
select n,x=cast(n as binary(2)),u=nchar(n) from nums where n between 19968 and 40869
19968 0x4e00 一
40869 0x9fa5
--以下两个条件用来判断字符串是否包含汉字
like n'%[-]%' collate chinese_prc_ci_as
like n'%[一-]%' collate chinese_prc_bin
--这是因为在以上两种不同的排序规则下,汉字的排列顺序是不同的。
--中文全角标点符号
select n,x=cast(n as binary(2)),uq=nchar(n),ub=nchar(n-65248) from nums where n between 65281 and 65374
select nchar(12288),nchar(32)
65281 0xff01 ! !
65374 0xff5e ~ ~
--以下条件用来判断字符串是否包含全角标点
like n'%[!-~]%' collate chinese_prc_bin
全角半角标点的转换:
sql code
--full2half
create function [dbo].[full2half](
@string nvarchar(max)
)
returns nvarchar(max)
as
/*
全角(fullwidth)转换为半角(halfwidth)
*/
begin
declare @chr nchar(1)
declare @i int
set @string = replace(@string,n' ',n' ')
set @i = patindex(n'%[!-~]%' collate latin1_general_bin,@string)
while @i > 0
begin
set @chr = substring(@string,@i,1)
set @string = replace(@string,@chr,nchar(unicode(@chr)-65248))
set @i = patindex(n'%[!-~]%' collate latin1_general_bin,@string)
end
return @string
end
go
create function [dbo].[half2full](
@string nvarchar(max)
)
returns nvarchar(max)
as
/*
半角(halfwidth)转换为全角(fullwidth)
*/
begin
declare @chr nchar(1)
declare @i int
set @string = replace(@string,n' ',n' ')
set @i = patindex(n'%[!-~]%' collate latin1_general_bin,@string)
while @i > 0
begin
set @chr = substring(@string,@i,1)
set @string = replace(@string,@chr,nchar(unicode(@chr)+65248))
set @i = patindex(n'%[!-~]%' collate latin1_general_bin,@string)
end
return @string
end
go