时间:2021-07-01 10:21:17 帮助过:67人阅读
先把需求说一下吧。从 MSSQL 中导出一个文章表,需要插入到 PHPCMS 中的内容表 phpcms_content 去,需要做到文章可以发布到不同的栏目中去。也就是说,需要复制一条记录,并修改其 catid,再插入到表尾的位置上。 MySQL 复制一条数据并插入的语句: INSERT I
先把需求说一下吧。从 MSSQL 中导出一个文章表,需要插入到 PHPCMS 中的内容表 phpcms_content 去,需要做到文章可以发布到不同的栏目中去。也就是说,需要复制一条记录,并修改其 catid,再插入到表尾的位置上。
MySQL 复制一条数据并插入的语句:
INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."')
大致为:insert into a SELECT id+1, ...(其它字段) FROM a ;
下面PHP具体程序:
$query = "SELECT * FROM articleincategory ORDER BY ArticleID "; $result = $connector -> query($query); $i = 0; while($myrow = $connector -> fetch_array($result)) { $r[$i]['aid'] = $myrow["ArticleID"]; $r[$i]['cateid'] = $myrow["CategoryID"]; $i++; } for($i = 0; $i < count($r); $i++) { if($i > 0) { if( $r[$i]['aid'] == $r[$i-1]['aid'] ) { echo '第 '. $i. ' 条数据 '. $r[$i]['aid'] .' 与前一条数据 '. $r[$i-1]['aid'] .' 重复'.'
'; $sql = " INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."') "; //$sql = " INSERT INTO phpcms_c_news (SELECT ".$r[$i]['aid']." + 520, template, titleintact, content, groupids_view, readpoint, author, copyfrom, paginationtype, maxcharperpage, sub_title FROM phpcms_c_news WHERE contentid = '".$r[$i-1]['aid']."') "; echo $sql.'
'; //$result = $connector -> query($sql); //INSERT INTO test (SELECT id + 10, name, class, score FROM test WHERE id = '1'); } else if( $r[$i]['aid'] != $r[$i-1]['aid'] ) { $sql = " UPDATE phpcms_content SET origin_cateid = '".$r[$i]['cateid']."' WHERE contentid = '".$r[$i]['aid']."' "; echo $sql.'
'; //$result = $connector -> query($sql); } } }
如果不需要插入,则更简单:insert into mytable (select * from mytable where id=1) ON DUPLICATE KEY UPDATE id=2;
或者: update mytable set id=2 where id=1;