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mysql用户自定义函数实例与部分问题解决方法

时间:2021-07-01 10:21:17 帮助过:2人阅读

一、查看创建函数的功能是否开启: mysql show variables like '%func%'; +-----------------------------------------+-------+ | Variable_name | Value | +-----------------------------------------+-------+ | log_bin_trust_function_creators | ON |

  一、查看创建函数的功能是否开启:

  mysql> show variables like '%func%';

  +-----------------------------------------+-------+

  | Variable_name | Value |

  +-----------------------------------------+-------+

  | log_bin_trust_function_creators | ON |

  +-----------------------------------------+-------+

  1 row in set (0.02 sec)

  二、如果Value处值为OFF,,则需将其开启。

  mysql> set global log_bin_trust_function_creators=1;

  use app02

  delimiter //

  mysql>DROP FUNCTION IF EXISTS `testhanshu`;

  CREATE FUNCTION `testhanshu`(`tustate` int)

  RETURNS varchar(2000)

  BEGIN

  declare oneAddr varchar(200) default '';

  declare allAddr varchar(2000) default '';

  DECLARE done INT DEFAULT FALSE;

  declare curl CURSOR for select utruename from tsys_user where ustate = tustate;

  DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;

  open curl;

  REPEAT

  FETCH curl INTO oneAddr;

  IF NOT done THEN

  set oneAddr = CONCAT(oneAddr, ';');

  set allAddr = CONCAT(allAddr, oneAddr);

  END IF;

  UNTIL done END REPEAT;

  close curl;

  RETURN allAddr;

  END;

  mysql>select testhanshu(1);

  在使用MySql自己定义的函数时,出现错误java.sql.SQLException: This function has none of DETERMINISTIC, NO SQL, or READS SQL DATA in its declaration and binary logging is enabled (you *might* want to use the less safe log_bin_trust_function_creators variable)

  解决办法有三种:

  1. 登录MySql客户端,执行: SET GLOBAL log_bin_trust_function_creators = 1;

  2.在登录MySQL服务器是,在服务启动时加上 “--log-bin-trust-function-creators=1 ”参数并设置为1。

  3.在my.ini(my.cnf)中的[mysqld]区段中加上 log-bin-trust-function-creators=1。

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