SqlServer

=背景介绍 -tableSales表 -第一次查询(2013销售员销售总额) select salesName, sum(extendedPrice) as sumprice13 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName -第二次查询(2014销售员销售总额) select sale

=>背景介绍

->tableSales表

->第一次查询(2013销售员销售总额)

select salesName, sum(extendedPrice) as sumprice13 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName

->第二次查询(2014销售员销售总额)

select salesName, sum(extendedPrice) as sumprice14 from tableSales where salesTime between '2014-01-01' and '2014-12-31' group by salesName

->如何获得销售员13、14年的销售总额？

A、首先，我想到的就是用union all，但不理想；

select salesName, sum(extendedPrice) as sumprice13, null as sumprice14 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName
union all
select salesName, null as sumprice13, sum(extendedPrice) as sumprice14 from tableSales where salesTime between '2014-01-01' and '2014-12-31' group by salesName

B最后，通过fredrickhu版主大大的指点，修改如下：

SELECT
a.salesName, a.sumprice13, b.sumprice14
FROM
(SELECT
salesName, SUM(extendedPrice) AS sumprice13
FROM
tableSales
WHERE
salesTime BETWEEN '2013-01-01' AND '2013-12-31'
GROUP BY
salesName
) AS a
INNER JOIN
(SELECT
salesName, SUM(extendedPrice) AS sumprice14
FROM
tableSales
WHERE
salesTime BETWEEN '2014-01-01' AND '2014-12-31'
GROUP BY
salesName
) AS b
ON a.salesName=b.salesName

最后再次感谢fredrickhu大大！谢谢！..风雨兼程...