时间:2021-07-01 10:21:17 帮助过:7人阅读
1。Sqlite 数据库: select count(*) from sqlite_master where table=*** sqlite_master 是 sqlite维护的系统表 2。SqlServer2000数据库 if exists(select 1 from sysobjects where name='表名' and xtype='u') print '存在' else print '不存在' 3。SqlSer
1。Sqlite 数据库:
select count(*) from sqlite_master where table=***
sqlite_master 是 sqlite维护的系统表
2。SqlServer2000数据库
if exists(select 1 from sysobjects where name='表名' and xtype='u')
print '存在'
else
print '不存在'
3。SqlServer2005数据库
SELECT ISNULL(OBJECTPROPERTY(OBJECT_ID('TableName'), 'IsUserTable'), 0)
存储过程中可以这样判断:
IF OBJECT_ID ('TableName', 'U') IS NOT NULL
4。access数据库
SELECT Count(*) AS RTab FROM MSysObjects WHERE (((MSysObjects.Name) Like "需判断的已知表名"));
5。MySql数据库
select 1 from information_schema.tables where table_name = 'account';
if found_rows() = 1 then
....
end if;