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MYSQL自定义函数之返回两个时间的指定类型时差

时间:2021-07-01 10:21:17 帮助过:19人阅读

该函数在MYSQL下编写,5.1版本测试通过。 函数需要传入三个参数,类型(用于区别应返回时差年、时差月...时差秒),起始时间(用于计算),结束时间(用于计算) 无 DELIMITER $$CREATE FUNCTION DateBetween (AType INT, ADateStart DATETIME, ADateEnd DATETIME)R

该函数在MYSQL下编写,5.1版本测试通过。
函数需要传入三个参数,类型(用于区别应返回时差年、时差月...时差秒),起始时间(用于计算),结束时间(用于计算) <无>
DELIMITER $$

CREATE FUNCTION DateBetween
  (AType INT, ADateStart DATETIME, ADateEnd DATETIME)
RETURNS BIGINT
BEGIN
DECLARE AResult BIGINT DEFAULT -1;
/*入参AType INT类型,结果类型 1:年 2:月 3:日 4:小时 5:分钟 6:秒钟 (必须在1-6内,否则结果返回-1)
*入参ADateStart DATETIME类型,起始时间 (必须是一个正确的日期参数)
*入参ADateEnd DATETIME类型,结束时间 (必须是一个正确的日期参数)
*返回值 BIGINT类型,返回起始之间与结束时间的指定时差 (成功返回计算出的时差,失败返回-1)
*/
IF ADateStart != '' AND ADateEnd != '' AND AType >=1 AND AType <= 6 THEN
  CASE AType
  WHEN 1 THEN
    SELECT TIMESTAMPDIFF(YEAR, ADateStart, ADateEnd) INTO AResult; 
  WHEN 2 THEN 
    SELECT TIMESTAMPDIFF(MONTH, ADateStart, ADateEnd) INTO AResult;   
  WHEN 3 THEN
    SELECT TIMESTAMPDIFF(DAY, ADateStart, ADateEnd) INTO AResult; 
  WHEN 4 THEN
    SELECT TIMESTAMPDIFF(HOUR, ADateStart, ADateEnd) INTO AResult; 
  WHEN 5 THEN
    SELECT TIMESTAMPDIFF(MINUTE, ADateStart, ADateEnd) INTO AResult; 
  WHEN 6 THEN
    SELECT TIMESTAMPDIFF(SECOND, ADateStart, ADateEnd) INTO AResult; 
  END CASE;
END IF;
RETURN(AResult); 
END$$


SELECT DateBetween(0, '2010-01-01 00:00:00', '2010-01-01 10:00:00');
SELECT DateBetween(1, '2001-01-01', '2010-01-01');
SELECT DateBetween(2, '2010-01-01', '2010-12-01');
SELECT DateBetween(3, '2010-01-01', '2010-01-31');
SELECT DateBetween(4, '2010-01-01 00:00:00', '2010-01-01 10:00:00');
SELECT DateBetween(5, '2010-01-01 00:00:00', '2010-01-01 10:00:00');
SELECT DateBetween(6, '2010-01-01 00:00:00', '2010-01-01 10:00:00');
SELECT DateBetween(7, '2010-01-01 00:00:00', '2010-01-01 10:00:00');

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