时间:2021-07-01 10:21:17 帮助过:29人阅读
Address 为Innodb表,AppUser 为FEDERATED表,下面的连接查询如果用INNER JOIN 就正常,用left join连接的结果Name全为null,即使有匹配的行,怀疑是mysql的bug
select a.*,b.Name from Address AS a
LEFT JOIN AppUser AS b ON b.AID = a.CheckAdminID
where a.AID=1006948
暂时解决办法:将AppUser改名AppUser1,建个视图AppUser引用AppUser1,结果正常。
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