时间:2021-07-01 10:21:17 帮助过:7人阅读
1 $sql=$empire->query("select table.title,lianxi,table.dizhi,table.id from table,table1 where table1.sid like concat( '%|',table.id,'|%') and table1.id=".$navinfor[id]."");2 while($r=$empire->fetch($sql))3 {4 $title=$r['title'];5 $lianxi=$r['lianxi'];6 $dizhi=$r['dizhi'];7 }
如下:两个表info,tag
info 表
id name
1 aa和bb
2 bb和cc
3 ee和dd
tag表
1 aa
2 bb
tag表中 name 匹配 info 中的name
这样写就有问题: select info.id, info.name from tag,info where info.name like ‘%'+tag.name+'%'
正确:
select info.id, info.name from tag,info where info.name like concat( '%',tag.name, '%')
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