时间:2021-07-01 10:21:17 帮助过:14人阅读
select可以取别名,delete不能。
1.使用mysql进行delete from操作时,若子查询的 FROM 字句和更新/删除对象使用同一张表,会出现错误。
mysql> DELETE FROM tab1 WHERE col1 = ( SELECT MAX( col1 ) FROM tab1 );
ERROR 1093 (HY000): You can’t specify target table ‘tab1′ for update in FROM clause
针对“同一张表”这个限制,撇开效率不谈,多数情况下都可以通过多加一层select 别名表来变通解决,像这样
DELETE FROM tab1
WHERE col1 = (
SELECT MAX( col1 )
FROM (
SELECT * FROM tab1
) AS t
);
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2. mysql delete from where in 时后面 的查询语句里不能加where条件
Sql代码
Sql代码
Sql代码
上面三种情况,只有中间的不能执行。
综合起来就是mysql delete from where in 时后面 的查询语句里不能加where条件
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3. delete from table... 这其中table不能使用别名
Sql代码
delete from student a where a.id in (1,2);(执行失败)
select a.* from student a where a.id in (1,2);(执行成功)
DELETE FROM v9_news WHERE title IN (SELECT title FROM (SELECT title FROM v9_news as newsb WHERE FROM_UNIXTIME(newsb.inputtime,'%Y-%m-%d')='2013-06-27' GROUP BY newsb.title HAVING COUNT(*) >1 ) b)
AND id NOT IN (SELECT id FROM (SELECT MIN(id) AS id FROM v9_news WHERE FROM_UNIXTIME(inputtime,'%Y-%m-%d')='2013-06-27' GROUP BY title HAVING COUNT(*)>1) c); TRUE!!
DELETE FROM v9_news AS news
WHERE news.title IN (SELECT title FROM v9_news as newsb WHERE FROM_UNIXTIME(newsb.inputtime,'%Y-%m-%d')='2013-06-27' GROUP BY newsb.title HAVING COUNT(*) >1 )
AND id NOT IN (SELECT MIN(id) FROM v9_news WHERE FROM_UNIXTIME(inputtime,'%Y-%m-%d')='2013-06-27' GROUP BY title HAVING COUNT(*)>1); FALSE!!