时间:2021-07-01 10:21:17 帮助过:16人阅读
结果如下:
mysql> SELECT * FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) a -> WHERE -> 3>( -> SELECT COUNT(*) -> FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) b -> WHERE a.cid=b.cid AND a.number)ORDER BY cid,number DESC;+------+----------------+--------+| cid | author | number |+------+----------------+--------+| 1 | test3 | 4 || 1 | test2 | 3 || 1 | test1 | 2 || 2 | test33 | 4 || 2 | test22 | 3 || 2 | test11 | 2 || 200 | 200test_nagios | 1 |+------+----------------+--------+7 rows in set (0.00 sec)
N就是取分组之后的最前面几个判断,N=3就是取前3个
-- 生成自动数字序列
SET @ROW=0;