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Mysql按月份为组进行统计排序_MySQL

时间:2021-07-01 10:21:17 帮助过:6人阅读

在数据库中我们经常用sql语句对表进行简单的统计排序,对于日期字段,我们可以简单的对其进行order。对于复杂一点的可以按日期中的年,月,日分别进行group,order。

按年份进行group,统计排序:

SELECT YERA(established_time),COUNT(*) AS num FROM `table_record` GROUP BY YEAR (established_time)

按月份进行group,统计排序:

方法一:简单实用

SELECT YEAR(established_time) AS 'year' , MONTH(established_time) AS 'month' , COUNT(*) AS 'count' FROM `table_record` 
GROUP BY YEAR (established_time) DESC, MONTH(established_time)

效果:

year month count

------ ------ --------

2014 1 8320

2014 2 5837

2014 3 25069

2014 4 29910

2014 5 25018

2014 6 17347

2014 7 1

2013 1 9114

2013 2 4258

方法二:利用MySql内置字符串连接函数 CONCAT(str1, str2, ...,str3) 。

SELECTCONCAT(YEAR(established_time),',',MONTH( established_time)) AS data_time ,COUNT(*) AS num FROM `table_record` #group by data_timeGROUP BY YEAR(established_time) DESC,MONTH( established_time)

效果:

data_time num

--------- --------

2014,1 8320

2014,2 5837

2014,3 25069

2014,4 29910

2014,5 25018

2014,6 17347

2014,7 1

2013,1 9114

2013,2 4258

注意这里不要用:

SELECTYEAR(established_time)+MONTH( established_time) as data_time 

这是错误的,它会造成2010+1=2011的这样的错误。

此外,若仅仅用下面语句,是统计的是多年来每月的数据。

SELECTMONTH(established_time) AS 'month' , COUNT(*) AS 'count' FROM `tb_gongshangju_record_beijing` GROUP BYMONTH(established_time) DESC


效果如下:

month count

------ --------

12 44952

11 49720

10 38587

9 48967

8 52874

7 54082

6 69532

5 76999

4 87289

3 85249

2 39997

1 49017

按日期day进行group,统计排序

SELECT YEAR(established_time) AS 'year' , MONTH(established_time) AS 'month' ,DAY(established_time) AS 'day', COUNT(*) AS 'count' FROM `table_record` WHERE table_record.`established_time` >= '2014-01-01'GROUP BY YEAR (established_time) DESC, MONTH(established_time) DESC ,DAY(established_time) DESC

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